The distance of the sound from the tuba is 4.82 m.
<h3>
Area of the tube</h3>
The area of the tuba is calculated as follows;
I = P/A
where;
- I is intensity of sound
- P is power
- A is area
A = P/I
A = 0.35 / (1.2 x 10⁻³)
A = 291.67 m²
<h3>Distance of the sound</h3>
Area = 4πr²
Thus, the distance of the sound from the tuba is 4.82 m.
Learn more about intensity of sound here: brainly.com/question/4431819
Answer:
x = A cos wt
Explanation:
To determine the position we are going to solve Newton's second law
F = m a
Spring complies with Hooke's law
F = -k x
And the acceleration of defined by
a = d²x / dt²
We substitute
- k x = m d²x / dt²
dx² / dt² + k/m x = 0
Let's call
w² = k / m
The solution to this type of differential equation is
x = A cos (wt + Ф)
Where A is the initial block displacement and the phase angle fi is determined by or some other initial condition.
In this case the body is released so that at the initial speed it is zero
From which we derive this expression
v = dx / dt = a w sin ( wt + Ф)
As the System is released for t = 0 the speed is v = 0
v = sin Ф = 0
Therefore Ф = 0
And the equation of motion is
x = A cos wt
Prejudice- <span>not based on reason or actual experience.
Bias- Usually based off of relation/knowledge or favor</span>
