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Nata [24]
3 years ago
8

Which statement explains why a rubber band analogy is not a perfect comparison for bonds in a substance when considering phase c

hanges? (1 point)
O For a phase change from solid to liquid, the bonds break completely and particles can move independently of each other.

O For a phase change from liquid to gas, the bonds do not break completely and particles can still slide past each other.

O For a phase change from solid to liquid, the bonds do not break completely and particles can still slide past each other.

O For a phase change from liquid to gas, the bonds break completely and particles can move independently of each other.
Chemistry
2 answers:
Aliun [14]3 years ago
5 0

The bonds in a substance breaks down in a phase change from liquid to gas and the molecules move independently of each other.

It is conventional to describe chemical bonds with the aid of elastic materials such as a rubber band. This analogy can only apply to covalent bonds between atoms in which the bonds between atoms are stretched.

However, in discussing the bonds in a substance when considering phase changes, this analogy breaks down because for a phase change from liquid to gas, the bonds break completely and particles can move independently of each other.

Learn more: brainly.com/question/6111443

Leno4ka [110]3 years ago
4 0

Answer:

1. kinetic energy

2. The particles within the system will have greater motion, and the temperature will increase.

3. Attractions occur due to electrostatic forces. When particles move fast enough, these forces can no longer keep particles together.

4. For a phase change from solid to liquid, the bonds do not break completely and particles can still slide past each other.

5. a sample of liquid benzene at 80ºC and a sample of gaseous benzene at 80ºC

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Two elements are studied. One has atomic number X and one has atomic number X+2. It is known that element X is a halogen. To wha
vladimir2022 [97]

Answer:

Group 1 (or IA)

Explanation:

If element X is a halogen, then it belongs to the group 17 (or VIIA, under a different notation).

For each extra unit of atomic number, the group number increases by 1. That means that the X+1 element would belong to the group 18 (or VIIIA). <em>The X+2 element would thus belong in the group 1 </em>(or IA) one period higher (higher as in numeric value, not as in position in the periodic table).

7 0
3 years ago
what property of the noble gases most likely prevented the gases from being readily/easily discovered?
Vlad [161]

These gases very rarely react, with others and also noble gases are odourless and colourless.

Explanation:

  • Noble gases will not react with anything so that is the reason why they are known as an inert gas.
  • Noble gases are present in group 18 on the periodic table and following the rule of the octet which is they completed their orbital by s2p6 which is the highest energy level.
  • Most elements are discovering through their reactivity with the other elements, commonly with oxygen. In the case of a noble gas, it is difficult for a scientist to work with the gases which have very less or no chemical property in terms of their reactivity.

7 0
3 years ago
List three action to reduce risk from hazard
Lena [83]

Answer:

Eliminate the hazard. ...

Substitute the hazard with a lesser risk. ...

Isolate the hazard. ...

Use engineering controls. ...

Use administrative controls. ...

Use personal protective equipment.

Explanation:

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8 0
3 years ago
Por qué los alimentos se dañan con mayor facilidad a temperatura ambiente que cuando están en la nevera?
ella [17]

Answer:

Esto se debe a que la heladera tiene mucha menor temperatura que la temperatura ambiente.

Esta menor temperatura ayuda a luchar contra los microorganismos que están en los alimentos (bacterias, hongos, etc) pues detiene en gran medida su repreduccion, la cual se ve maximizada en los rangos entre 5°C y 60°C, tal que la temperatura ambiente suele estar en el rango donde los microorganismos prosperan y se reproducen, es por ello que los alimentos se conservan mucho mejor en ambientes fríos (como la nevera) que en temperatura ambiente.

4 0
3 years ago
The procedure for testing your unknown solution in this week's lab is identical to the procedure which you conducted in Week 1.
lawyer [7]

Answer:

The correct answer is option C. The unknown solution definitely has Hg22+ present.

Explanation:

In the analysis of group 1 metal cation, the unknown solution is treated with sufficient quantity of 6 M HCl solution and if group 1 metal cations are present then white precipitate of Agcl, PbCl2 or Hg2Cl2 is formed. The precipitate of PbCl2 is soluble in hot water but the other two remains insoluble after treating with hot water. Precipitate of AgCl disappears upon treatment of NH3 solution but Hg2Cl2 becomes black in the reaction with NH3. The black Colour appears due to the formation of metallic Hg.

Balanced chemical equation of the reation is -

Hg2Cl2 + 2NH3  ---------> HgNH2Cl (white ppt.) + Hg (black ppt.) + NH4Cl

Therefore, from the given information the conclusion which can be drawn is that the unknown solution definitely has Hg22+ present.

8 0
3 years ago
Read 2 more answers
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