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3 years ago

When a chemical reaction is in equilibrium,

Chemistry

1 answer:

34kurt3 years ago

7 0

Answer: b. there is no net change in the amount of substrates or products.

Explanation:

The reactions which do not go on completion and in which the reactant forms product and the products goes back to the reactants simultaneously are known as equilibrium reactions.

Equilibrium state is the state when reactants and products are present but the concentrations does not change with time.

$A\rightleftharpoons B$

For a chemical equilibrium reaction, equilibrium state is achieved when the rate of forward reaction becomes equals to rate of the backward reaction.

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oils will dissolve best in solvents that are? A. polar B. nonpolar C. either polar or nonpolar D. neither polar nor nonpolar

Genrish500 [490]

The answer is <span>B. nonpolar.

Polar molecules dissolve best in polar solvents while nonpolar molecules dissolve best in nonpolar solvents. </span>Oils are nonpolar. So, they will dissolve best in nonpolar solvents. If you put oil in some polar solvent, such as water, it will hardly dissolve.

4 0

3 years ago

(6) Compare a CSTR with a PFR below. a. A flow of 0.3 m3/s enters a CSTR (volume of 200 m3) with an initial concentration of spe

Dmitry [639]

Answer:

Explanation:

Given that:

The flow rate Q = 0.3 m³/s

Volume (V) = 200 m³

Initial concentration $C_o$ = 2.00 ms/l

reaction rate K = 5.09 hr⁻¹

Recall that:

$time (t) = \dfrac{V}{Q}$

$time (t) = \dfrac{200}{0.3}$

$time (t) = 666.66 \ sec$

$time (t) = \dfrac{666.66 }{3600} hrs$

$time (t) = 0.185 hrs$

$\text{Using First Order Reaction:}$

$\dfrac{dc}{dt}=kc$

where;

$t = \dfrac{1}{k} \Big( \dfrac{C_o}{C_e}-1 \Big)$

$0.185 = \dfrac{1}{5.09} \Big ( \dfrac{200}{C_e}- 1 \Big)$

$0.942 = \Big ( \dfrac{200}{C_e}- 1 \Big)$

$1+ 0.942 = \Big ( \dfrac{200}{C_e} \Big)$

$\dfrac{200}{C_e} = 1.942$

$C_e = \dfrac{200}{1.942}$

$\mathbf{C_e = 102.98 \ mg/l}$

Thus; the concentration of species in the reactant = 102.98 mg/l

b). If the plug flow reactor has the same efficiency as CSTR, Then:

$t _{PFR} = \dfrac{1}{k} \Big [ In ( \dfrac{C_o}{C_e}) \Big ]$

$\dfrac{V_{PFR}}{Q_{PFR}} = \dfrac{1}{k} \Big [ In ( \dfrac{C_o}{C_e}) \Big ]$

$\dfrac{V_{PFR}}{Q_{PFR}} = \dfrac{1}{5.09} \Big [ In ( \dfrac{200}{102.96}) \Big ]$

$\dfrac{V_{PFR}}{Q_{PFR}} =0.196 \Big [ In ( 1.942) \Big ]$

$\dfrac{V_{PFR}}{Q_{PFR}} =0.196(0.663)$

$\dfrac{V_{PFR}}{0.3 hrs} =0.196(0.663)$

$\dfrac{V_{PFR}}{0.3*3600 sec} =0.196(0.663)$

$V_{PFR} =0.196(0.663)*0.3*3600$

$V_{PFR} = 140.34 \ m^3$

The volume of the PFR is ≅ 140 m³

3 0

3 years ago

Blank + BaCl2 = BaSO4 + 2NaCl

crimeas [40]

The blank is filled by Na₂SO₄, and the complete equation for the double displacement reaction is:

Na₂SO₄ + BaCl₂ = BaSO₄ + 2 NaCl

<h3>What is a double displacement reaction?</h3>

It is a reaction in which both reactants exchange anions and cations.

Let's consider the following incomplete double displacement reaction.

_____ + BaCl₂ = BaSO₄ + 2 NaCl

If we compare the left and right sides, we can see that the missing ions in the left side are Na⁺ and SO₄²⁻. Thus, the missing compound is Na₂SO₄. The complete equation is:

Na₂SO₄ + BaCl₂ = BaSO₄ + 2 NaCl

Learn more about double displacement here: brainly.com/question/23918356

#SPJ1

5 0

2 years ago

7.The following symbol is used to represent the particles in what type of radiation?Select one:a. Alphab. Betac. Gammad. Neutron

laiz [17]

Explanation:

The emission of a beta particle is the result of the rearrangement of the unstable nucleus of the radioactive atom in order to acquire stability. For that, a phenomenon occurs in the nucleus, in which a neutron decomposes giving rise to three new particles: a proton, an electron (β particle), and a neutrino. The antineutrino and electron are emitted. The proton, however, remains in the nucleus.

The symbol is used to represent beta particles.

Answer: b. Beta

5 0

1 year ago

When reactants and products are being formed at an equal rate in a chemical reaction, the ____. a. reaction is endergonic b. fre

attashe74 [19]

<h2>The answer is option b "free energy is zero"</h2>

Explanation

The reaction that has negative free energy are called exergonic reactions that means the reactants have more free energy than the product formed.
The reaction that has positive free energy are called endergonic reactions that means the final state or the products formed have more free energy than the initial state or the reactants.
The reaction that has zero free energy occurs when the free energy of both reactants and the products are same hence the rate of formation of products and reactants are equal.
Therefore, when reactants and products are being formed at an equal rate the free energy is zero.

3 0

3 years ago