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GalinKa [24]
3 years ago
15

Give the general word equation for the net reaction for the preparation of amines. alkyl halide + 2 (either ammonia or nitrogen

gas)→ alkyl amine + (either ammonium halide or nitrous halide)
Chemistry
1 answer:
trapecia [35]3 years ago
4 0

Answer:

alkyl halide + 2 (ammonia) → alkyl amine + ammonium halide

Explanation:

In this type of preparation of alkyl amine this process works through substitution nucleophilic second order reaction and the nucleophile in this case is the ammonia and the leaving group will be the chloride ion

When ammonia attacks opposite to the way in which leaving group leaves, the chloride ion will be leaved and the nitrogen attains positive charge

So one of the hydrogen attached to the nitrogen will be removed and as there is another mole of ammonia and as ammonia is a base, it takes that hydrogen and it will form ammonium ion and to this ion chloride ion will get attracted as both have opposite charges and at last alkyl amine and ammonium halide will be formed    

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A sample of He gas (3.0 L) at 5.6 atm and 25°C was combined with 4.5 L of Ne gas at 3.6 atm and 25°C at constant temperature in
In-s [12.5K]

Answer:

3.6667

Explanation:

<u>For helium gas:</u>

Using Boyle's law  

{P_1}\times {V_1}={P_2}\times {V_2}

Given ,  

V₁ = 3.0 L

V₂ = 9.0 L

P₁ = 5.6 atm

P₂ = ?

Using above equation as:

{P_1}\times {V_1}={P_2}\times {V_2}

{5.6}\times {3.0}={P_2}\times {9.0} atm

{P_2}=\frac {{5.6}\times {3.0}}{9.0} atm

{P_1}=1.8667\ atm

<u>The pressure exerted by the helium gas in 9.0 L flask is 1.8667 atm</u>

<u>For Neon gas:</u>

Using Boyle's law  

{P_1}\times {V_1}={P_2}\times {V_2}

Given ,  

V₁ = 4.5 L

V₂ = 9.0 L

P₁ = 3.6 atm

P₂ = ?

Using above equation as:

{P_1}\times {V_1}={P_2}\times {V_2}

{3.6}\times {4.5}={P_2}\times {9.0} atm

{P_2}=\frac {{3.6}\times {4.5}}{9.0} atm

{P_1}=1.8\ atm

<u>The pressure exerted by the neon gas in 9.0 L flask is 1.8 atm</u>

<u>Thus total pressure = 1.8667 + 1.8 atm = 3.6667 atm.</u>

6 0
3 years ago
During the combustion of NH3, there is an increase in the amount of oxygen present, from 5 to 20 moles while the amount of NH3 r
borishaifa [10]

Explanation:

The ratio of NH3 to NO produced will remain constant since NH3 is the limiting reactant.

Here in this reaction for every 4 moles of ammonia and 5 moles of oxygen gas , 4 moles of NO and 6 moles of water are formed.

So when the amount of oxygen gas is increased to 20 moles without changing the amount of ammonia , the amount of NO formed does not increase as ammonia becomes the limiting reactant.

6 0
3 years ago
Is cis 4-tert-butylcyclohexanol more polar than trans? I recently did a reduction reaction of 4-tert-butylcyclohexanol with sodi
natima [27]

Cis is more polar than trans. Cis would be \_/ and trans is /-/. I am hoping that this answer has satisfied your query about and it will be able to help you, and if you’d like, feel free to ask another question.

7 0
3 years ago
A common antacid contains the acid-neutralizing agent sodium hydrogen carbonate. Write the chemical formula for sodium hydrogen
kaheart [24]
Sodium hydrogen carbonate has:
sodium \:  ion ( {Na}^{+}), hydrogen \\  ion ( {H}^{+}), and \:  carbonate \\ ion ( {CO3}^{2-})
The + from Na+ and + from H+ makes 2+, and therefore the 2- from CO3 evens the charges to neutral.

Not to be confused with Sodium Carbonate, (Na2CO3), which lack an H, Sodium Hydrogen Carbonate is sometimes shortened to just Sodium Bicarbonate. It is used in the kitchen (cooking) as "baking soda."

Formula: NaHCO3
3 0
3 years ago
The pH of a solution is 9.63 ± 0.03 . What is the concentration of H + in the solution and its absolute uncertainty?
Helga [31]

Explanation:

The pH of the solution is 9.63 ± 0.03.

we know that

pH= -log[H+]

⇒[H+] =10^{-pH}

=10^{-9.63} = 2.34\times10^{-10}

Now to find absolute error we use the formula

Absolute error/[H+] =ln10(uncertainity)

Absolute error = ln10×[H+] ×0.03

=ln10\times2.34\times10^{-10}\times0.03

= 9.45\times10^{-12}

8 0
3 years ago
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