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2 years ago

PLEASE HELP ME 20 POINTS AND I WILL MARK BRAINLIEST!!!

Physics

2 answers:

Andreyy892 years ago

7 0

B. a homogeneous mixture in which one substance is dissolved into another

wolverine [178]2 years ago

4 0

Think it's b homeslice

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A hot-air balloon plus cargo has a mass of 308 kg and a volume of 2910 m3 on a day when the outside air density is 1.22 kg/m3. T

lesya [120]

9514 1404 393

Answer:

1.114 kg/m³

Explanation:

The total mass of the air in the balloon and the balloon + cargo will be the mass of the displaced air. If d is the density of the air in the balloon, then we have ...

2910d +308 = 2910×1.22

Solving for d, we find ...

2910d = 2919(1.22) -308

d = 1.22 -308/2910

d ≈ 1.114 . . . kg/m³

The density of the hot air is about 1.114 kg/m³.

6 0

2 years ago

On a sunny day, a family decided to take sail on a nearby lake. During sailing the wind applies a force of 25N north on the sail

natka813 [3]

Answer:

its n

Explanation:

4 0

2 years ago

Under normal circumstances: _________

Nuetrik [128]

Answer:

Fetal Hb binds oxygen more tightly than adult Hb (not option a)

3 0

2 years ago

Consider the following three statements: For any electromagnetic radiation, the product of the wavelength and the frequency is a

boyakko [2]

Answer:

The correct answer is B. Statements (i) and (ii) are true.

Explanation:

Fisrt statement:

Electromagnetic radiation such as wave, wavelength λ and oscillation frequency ν are related by a constant, the speed of light. The equation is given by:

$c= \lambda \nu$

So the first statement is true.

Second statement:

$c=\lambda \nu\\c= 3.0 A \times 1.0\times 10^{18} Hz\\c= 3.0\times 10^{-10} m \times 1.0\times 10^{18} s^{-1}\\c=3\times 10^8 \frac{m}{s}$

The value of c in the vacuum is 3×10⁸ m/s. Hence, the second statement is true.

Third statement:

The speed of any electromagnetic radiation is constant regardless the type of radiation.

Hence, the third statement is false.

8 0

2 years ago

(Figure 1) shows the angular-velocity-versus-time graph for a particle moving in a circle. How many revolutions does the object

Travka [436]

Answer: 10.34

Explanation:

Given

$\omega -t$ graph for a particle is given

angle turned by the particle in radians is given by the area under $\omega -t$ graph

The area is given by

$A=20\times (2-0)+10(4-2)+\dfrac{1}{2}\times (20-10)\times (3-2)\\A=40+20+5=65\ rad$

Revolutions(N) made by the object is given by

$N=\dfrac{65}{2\pi }=10.34$

4 0

2 years ago