Pythagoras Theorem:
hipotenuse²=leg₁²+leg₂²
First posible triangle:
hypotenuse=13 (13²=169)
leg₁=12 ( 12²=144)
leg₂=5 (5²=25)
13³=144 + 25
Answer:can be side lengths of a triangle
Second triangle:
hypotenuse=12.6 (12.6²=158.76)
leg₁=6.7 ( 6.7²=44.89)
leg₂=6.5 (6.5²=42.25)
leg₁²+leg₂²=44.89+42.25=87.14≠158.76
Answer: cannot be side lenghts of a triangle.
third triangle:
hypotenuse=13 (13²=169)
leg₁=12 ( 12²=144)
leg₂=11 (11²=121)
leg₁²+leg₂²=144+121=265≠169
Answer: cannot be side lenghts of a triangle.
fourth triangle:
hypotenuse=13 (13²=169)
leg₁=6 ( 6²=36)
leg₂=4 (4²=16)
leg₁²+leg₁²=36+16=52≠169
Answer: cannot be side lenghts of a triangle.
10/40 * 100= 25%
25% is the answer.
Answer:
13/15
Step-by-step explanation:
2/3 + 1/5
You first,
- Find the L. C. M, i hope u know the full name, if u don't, let me know in the comment section.
- the L. C. M is 15
- therefore it will be 10+3/15
- 13/15
Recognize that you must combine "like" terms. 5x^2y and x^2y are "like" terms.
Adding them together, you get 6x^2y.
Now add 2xy^2 to 6x^2y. These are NOT "like" terms, so you end up with
6x^2y+2xy^2 as your final answer. This answer is acceptable as is.
However, you could factor out the common factors: 2xy(3x+y).
Answer:
20 miles
Step-by-step explanation:
I'm not sure if that is exactly how you solve it but
If its
8x+4 as the equation and x is the number of hours run
the total number of miles run should be 20 miles
8(2)+4=20
