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2 years ago

Willingness to take turns is one way we can express our attitudes in

1 answer:

7 0

<span>The correct option is A, that is, non-verbal communication. Non-verbal communication is defined as the kind of communication that are passed across without using words. Examples of this are: shaking of hands, hugging, back-patting, facial expression, eye-contact and every form of communication that are make use of without the usage of words.</span>

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What is the strength of an electric field that will put a force of<br> 1.28 x 10-15 N on a proton?

PilotLPTM [1.2K]

Answer: E = 7,490.6 N/C

Explanation:

If we have a field E, and a particle with a charge q, the force that the particle experiences is:

F = E*q

In this case, we know that the force is:

F = 1.2*10^(-15) N

And we know that the particle is a proton, where the charge of a proton is:

q = 1.602*10^(-19) C

Then we can replace these two values in the equation to get:

1.2*10^(-15) N = E*1.602*10^(-19) C

We just need to isolate E.

(1.2*10^(-15) N)/(1.602*10^(-19) C) = E

7,490.6 N/C = E

That is the strength of the electric field.

8 0

2 years ago

A point from which the position of other objects can be described is called what?

Alisiya [41]

Answer:

Reference Point

Explanation:

3 0

3 years ago

Two 1.9 kg masses are 1.1 m apart (center to center) on a frictionless table. Each has + 9.6 μC of charge.

Anni [7]

Answer:

F= 0.6 N

Explanation:

Fe(electrical force)= $k q1q2/r^2$

$k=9*10^9\\q1=-9.6 *10^-6 C\\q2= -9.6*10^-6 C\\r= 1.1m$

So,

$F=\frac{9*10^9*-9.6 *10^-6 C* -9.6*10^-6 C}{1.1^2}$

$F= 0.6 N$

5 0

2 years ago

a student calculates experimentally the value of density of an iron as 4.4 gcm³. if the actual density of an iron is 7.6 gcm³, c

ser-zykov [4K]

Hola!

Percentage Error is a measurement of the discrepancy between an observed and a true, or accepted value.

[ refer the attachment. ]

According to Question,

% error = $\frac{7.4 - 7.6}{7.6}$ × 100

= 2.631 % = 2.7 % (approximately.)

hope it helps!

5 0

2 years ago

Along the remote Racetrack Playa in Death valley, California, stones sometimes gouge out prominent trails in the desert floor, a

REY [17]

Answer:

F = 196 N

Explanation:

For this exercise we will use Newton's second law, we define a reference system with the x axis in the direction of movement of the stones and the y axis vertically

Y axis

N- W = 0

N = mg

X axis

F -fr = ma

In this case, they ask us for the force to keep moving, so the stones go at constant speed, which implies that the acceleration is zero.

F- fr = 0

F = fr

the friction force has the equation

fr = μ N

fr = μ mg

we substitute

F = μ mg

let's calculate

F = 0.80 9.8 25

F = 196 N

8 0

2 years ago