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Volgvan
2 years ago
12

Dexter uses a compass to walk 140m due east. What is his distance and displacement?

Physics
1 answer:
solmaris [256]2 years ago
3 0
The distance is 140 m and the displacement is 140 m E. Displacement can change though. For example, if Dexter walked 140 m east then walked 40 meters west the displacement would be 100 m E. Displacement is just how far away an object is from the start.
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An object is dropped from a height of 75.0 m above ground level. (a) determine the distance traveled during the first second.
barxatty [35]

The relevant formula we can use in this case would be:

h = v0 t + 0.5 g t^2

where,

h = height or distance travelled

v0 = initial velocity = 0 since it was dropped

t = time = 1 seconds

g = 9.8 m/s^2

 

So calculating for height h:

h = 0 + 0.5 * 9.8 m/s^2 * (1 s)^2

<span>h = 4.9 meters</span>

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Which statement is true?
m_a_m_a [10]
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3 years ago
Read 2 more answers
How do i solve this step by step
NikAS [45]

Answer:

176.4 meters

Explanation:

The first equation is for average velocity.  The other three are the constant acceleration equations you'll need to know.

v = at + v₀

v² = v₀² + 2a(x − x₀)

x = x₀ + v₀ t + ½ at²

x is the final position

x₀ is the initial position

v is the final velocity

v₀ is the initial velocity

t is time

a is acceleration

Notice that the first equation is independent of position.

The second equation is independent of time.

The third equation is independent of final velocity.

So knowing which information you <em>don't</em> have will point you to which equation you should use.

Let's begin:

"Which one would be best to find the distance the object fell from free-fall if it fell for six seconds, assuming if fell in the absence of air resistance and it still hasn't hit the ground?  Solve this problem and show all steps of work."

We want to find the distance (change in position).  We're given the time (t = 6 s) and we're given the acceleration (free fall without air resistance, so a = -9.8 m/s²).

We aren't given the final velocity, so the equation we should use is the third one:

y = y₀ + v₀ t + ½ at²

Unfortunately, we aren't told the initial velocity, but if we assume that the object starts at rest, then v₀ = 0 m/s.  Substituting all values:

y = y₀ + (0 m/s) (6 s) + ½ (-9.8 m/s²) (6 s)²

y − y₀ = -176.4 m

The displacement is -176.4 m.  Distance is the magnitude of displacement, so we can say the object fell 176.4 meters.

3 0
3 years ago
A car with an initial speed of 6.5 m/s accelerates at a uniform rate of 0.92 m/s2 for 3.6 s. Find the final speed of the car dur
geniusboy [140]
U = 6.5 m/s, initial speed
t = 3.6 s, time
a = 0.92 m/s², acceleration

Let v = the final velocity.
Then
v = u +at
v = (6.5 m/s) + (0.92 m/s²)*(3.6 s) = 9.812 m/s

Answer: 9.81 m/s 
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How did Micheal Faraday discover the magnetic theory and when?​
serious [3.7K]

Answer:

Faraday made his first discovery of electromagnetism in 1821.  He took the work of Oersted and Ampère on the magnetic properties of electrical currents as a starting point and in 1831 achieved an electrical current from a changing magnetic field, a phenomenon known as electromagnetic induction.

Explanation:

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