Answer:
The centripetal force on the boy = 2.888 N
Explanation:
Given:
m = 30 kg
r = 1.5 m
v = 0.38 m/s
To Find:
The centripetal force on the boy = ?
Solution:
F = m x v^2 / r
F = 30 kg x (0.38 m/s)^2 / 1.5 m
F = 30 x 0.1444 / 1.5
F = 2.888 N
Therefore,
The centripetal force on the boy = 2.888 N
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Answer:
Acceleration is the rate of change of velocity. What is commonly said as ‘ten meter per second squared’ can bee broken down into ‘ten meter per second per second.’ This gives us the true meaning of the term acceleration.
Just like ‘ten meter per second’ means increasing the displacement by ten meters every second, ‘ten meter per second per second’ means increasing the velocity by ten meters per second every second.
So, basically if you consider the case of a free fall motion, where ‘t’ stands for time and ‘v’ stand for velocity at that instant:
At,
t=0, v=0 m/s
t=1, v=0+10 m/s;
t=2, v=0+10+10 m/s;
t=3, v=0+10+10+10 m/s;
This can also be thought as a Arithmetic Progression where common difference ‘D’ is the acceleration(a), since it adds a 10 m/s to velocity every second and the first term ‘A’ stands for the initial velocity (u). Using this approach we can derive to the first equation of motion:
v = u + at
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Explanation:
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Answer:
Voltage, V = 0.0524 volts
Explanation:
Thickness of the membrane, 
Electric field strength, 
We need to find the voltage across it. The relationship between the voltage, electric field and the distance is given by :


V = 0.0524 volts
So, the voltage across the thick membrane is 0.0524 volts. Hence, this is the required solution.
Charge = Current/time
Q = It
t = Q/I = 15/20 = 0.75 s
(a) As the car is moving with constant velocity, it means the rate change of velocity does not change, therefore the average acceleration of the car is zero.
Thus, there is no acceleration, when velocity is constant.
(b) Average acceleration,

Here, v is final velocity and u is the initial velocity and
is the time interval.
As twelve seconds later, the car is halfway around the track and traveling in the opposite direction with the same speed, therefore

Thus, the average acceleration of the car is
in the direction to the left.