Answer:
An Empty Tank Is Slowly Filled With Air. Water Is Then Added To The Tank, Decreasing The Volume For The Air In The Tank. The Temperature Remains Constant
Explanation:
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Answer:
v = 2.94 m/s
Explanation:
When the spring is compressed, its potential energy is equal to (1/2)kx^2, where k is the spring constant and x is the distance compressed. At this point there is no kinetic energy due to there being no movement, meaning the net energy in the system is (1/2)kx^2.
Once the spring leaves the system, it will be moving at a constant velocity v, if friction is ignored. At this time, its kinetic energy will be (1/2)mv^2. It won't have any spring potential energy, making the net energy (1/2)mv^2.
Because of the conservation of energy, these two values can be set equal to each other, since energy will not be gained or lost while the spring is decompressing. That means
(1/2)kx^2 = (1/2)mv^2
kx^2 = mv^2
v^2 = (kx^2)/m
v = sqrt((kx^2)/m)
v = x * sqrt(k/m)
v = 0.122 * sqrt(125/0.215) <--- units converted to m and kg
v = 2.94 m/s
To find the force we use the formula,
F = ma , where m is mass and a acceleration
Using the formula,
F = ma
F = 0.42 x 14.8
F = 6.216 N / 6.22 N
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The force is given by the product of mass and the acceleration thus the force is given
8480/32 is equal to 265 kg