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2 years ago

Does light have a shadow?

Physics

2 answers:

NeX [460]2 years ago

5 0

Answer:

light itself doesn't have a shadow

Explanation:

light emits light to where things around the light may create the shadows

borishaifa [10]2 years ago

4 0

Answer:

Explanation:

Actually it the complete opposite. A shadow is an absence (or decrease of) of light because an object blocking its path.

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In one hour Earth receives enough solar energy to meet the energy needs of the world for

erastova [34]

I have read that it is enough energy to power the needs of civilization for an entire year.

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3 years ago

If you were to drop a rock from a tall building, assuming that it had not yet hit the ground, and neglecting air resistance, aft

elena-14-01-66 [18.8K]

Since the object is dropped from some height so its initial speed must be zero

acceleration of the object is due to gravity

so we can use kinematics to find the time it will take to drop by x = 22 m

$\delta x = v_i * t + \frac{1}{2}at^2$

$22 = 0 + \frac{1}{2}*9.8*t^2$

$t = 2.12 s$

Now the speed after 2.12 s will be given as

$v_f = v_i + at$

$v_f = 0 + 9.8 * 2.12$

$v_f = 20.8 m/s$

so above is the speed and time

5 0

3 years ago

Which of the following has the most potential energy?

Alex

A Car at the top of a hill.

It is because in that case, produce of mass and height is highest which is directly proportional to potential energy

In short, Your Answer would be Option A

Hope this helps!

3 0

3 years ago

Read 2 more answers

The loop is in a magnetic field 0.20 T whose direction is perpendicular to the plane of the loop. At t = 0, the loop has area A

love history [14]

Answer:

Part a)

$EMF = 14 \times 10^{-3} V$

Part b)

$EMF = 15.67 \times 10^{-3} V$

Explanation:

As we know that magnetic flux through the loop is given as

$\phi = B.A$

now we have

$\phi = B\pi r^2$

now rate of change in flux is given as

$\frac{d\phi}{dt} = B(2\pi r)\frac{dr}{dt}$

now we know that

$A = \pi r^2$

$0.285 = \pi r^2$

$r = 0.30 m$

Now plug in all data

$EMF = (0.20)\times 2\pi\times (0.30) \times (0.037)$

$EMF = 14 \times 10^{-3} V$

Part b)

Now the radius of the loop after t = 1 s

$r_1 = r_0 + \frac{dr}{dt}$

$r_1 = 0.30 + 0.037$

$r_1 = 0.337 m$

Now plug in data in above equation

$EMF = (0.20)\times 2\pi\times (0.337) \times (0.037)$

$EMF = 15.67 \times 10^{-3} V$

5 0

3 years ago

Kinetic energy is greatest when a roller coaster

mr Goodwill [35]

Hey Dave... you need to learn and I want you to improve I believe it to be at the bottom of the hill. Please read your siht homie

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3 years ago