Answer:
114 K
Explanation:
Given data
- Volume of oxygen (V): 629 mL = 0.629 L
- Pressure of oxygen (P): 0.500 atm
- Moles of oxygen (n): 0.0337 mol
We can calculate the temperature at which the student collected the oxygen using the ideal gas equation.

The oxygen gas was collected at 114 K.
Answer:
6.8 mole of O₂
Explanation:
Given expression:
2H₂ + O₂ → 2H₂O
Number of moles of H₂ = 13.6moles
Unknown:
Number of moles of O₂ = ?
Solution:
In the given problem, we are to find the number of moles of oxygen gas that will use up 13.6mole of hydrogen gas;
From the reaction equation;
2 mole of H₂ will completely react with 1 mole of O₂
13.6 moles of H₂ will completely be used up by
mole of O₂
= 6.8 mole of O₂
I would say that the answer has to be C
Since there is no change in mols on both sides of the equation the mass is constant
A) can enter from the surroundings, but cannot escape to the surroundings