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Bess [88]
3 years ago
5

If 15.0 grams of ca combines completely with 12.0 grams of s to form a compound, what is the percent composition of s in the com

pound?
Chemistry
2 answers:
Gnoma [55]3 years ago
5 0
<span>44.4% by weight
   Percent composition is the percent by mass in a composition. Since this problem states "combines completely", I will assume that both reactants are fully consumed and that the resulting product has the combined mass of both reactants. If that's the case, then we simply divide the mass of sulfur by the mass of the compound. So: X = 12.0/(12.0 + 15.0) = 12.0/27.0 = 0.444444 = 44.4%</span>
Oduvanchick [21]3 years ago
4 0
<span>The percent composition of s in the compound is 44.4%.
</span>
No. of grams of ca = 15
no. of grams of S = 12
<span>percent composition of s in the compound = 12/(15 + 12) x 100
= 12/27 x 100
= 0.44 x 100
= 44.4%</span>
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mixer [17]

Answer:

sp3 - 1,2,13,16,18,19

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sp- 0

Explanation:

Hybridization is the idea that atomic orbitals fuse to form newly hybridized orbitals, which in turn, influences molecular geometry and bonding properties (Chemlibretexts).

Carbon atoms that are singly bonded are sp3 hybridized, carbon atoms that are doubly bonded are sp2 hybridized while carbon atoms that are triply bonded are sp hybridized.

Sp3 hybridized atoms have a tetrahedral geometry, sp2 hybridized atoms have a trigonal planar geometry while an sp hybridized atom has a linear geometry.

The hybridization state of each atom in the compound has been shown in the answer section.

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