Question

a country population in 1993 was 94 million in 1999 it was 99 million estimate the population in 2005 using the exponential growth formula round your answer to the nearest million p=aekt

Answer 1

K = ln(ending amt/bgng amount)/6 years
k = ln(99,000,000/94,000,000) / 6 years
k = ln( 1.0531914894 ) / 6 years
k = 0.0518250679 / 6
k = 0.0086375113

Final population = bgng*e^k*years
Where "e" is the mathematical constant 2.718281828
Final population = 94,000,000*e^0.0086375113*12
Final population = 94,000,000*e^0.1036501356
Final population = 94,000,000*  1.1092123132
Final population = 104,265,957