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velikii [3]
3 years ago
9

a country population in 1993 was 94 million in 1999 it was 99 million estimate the population in 2005 using the exponential grow

th formula round your answer to the nearest million p=aekt
Mathematics
1 answer:
tester [92]3 years ago
5 0
K = ln(ending amt/bgng amount)/6 years
k = ln(99,000,000/94,000,000) / 6 years
k = ln( <span> <span> <span> 1.0531914894 </span> </span> </span> ) / 6 years
k = <span> <span> <span> 0.0518250679 </span> </span> </span> / 6
k = <span> <span> <span> 0.0086375113</span></span></span>

Final population = bgng*e^k*years
Where "e" is the mathematical constant 2.718281828
Final population = 94,000,000*e^<span>0.0086375113*12</span>
Final population = 94,000,000*e^<span><span><span>0.1036501356 </span> </span> </span>
Final population = 94,000,000*  <span> <span> <span> 1.1092123132 </span> </span> </span> <span><span> </span> </span>
Final population = <span> <span> <span> 104,265,957 </span> </span> </span>


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Answer:

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Step-by-step explanation:

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angle F = 42 degrees

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we can now insert the values into the formula

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cross-multiply

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We will now proceed to find side EF

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angle E = 49 degrees

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d= EF = ?

we can now proceed to insert the values into the formula

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cross-multiply

d sin 49° = 10 sin 89°

divide both-side of the equation by sin 49°

d= 10 sin 89°/sin 49°

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This implies that length EF = 13.248

perimeter of ΔDEF = length DE + length EF + length DF

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