How dose blood pressure change as blood moves through arteries capillaries and veins

A charged particle moving in the magnetic field. For which angle magnetic force acting on charged particle is maximum.?

AnnyKZ [126]

Answer:

90o angle

Thus magnetic force on charged particle is maximum when it moves at a 90o angle to the field.

3 0

3 years ago

Spaceship A is 10 meters long and approaching you from the south at a speed of.7c while spaceship B, which is also 10 meters lon

Valentin [98]

Answer:

a) 0.94 C

b) 7.14 m

c) 3.11 m

d) 1.40 s

e) 2.93 s

Explanation:

First we need to set up a coordinate system. This will have the positive X axis pointing north. So spaceship A has positive speed, and spaceship B has negative speed.

The Lorentz transformation for speed is:

$u' = \frac{u - v}{1 - \frac{u*v}{c^2}}$

u: speed of spaceship A as observed by you

v: speed of spaceship B as observed by you

In the case of the speed of spaceship A as observed by spaceship B:

$u' = \frac{0.7c - (-0.7c)}{1 - \frac{0.7c*(-0.7c)}{c^2}} = 0.94c$

The transform for lengths is:

$L = L0 * \sqrt{1 - \frac{v^2}{c^2}}$

For the case of spaceship A as observed by you:

$L = 10 m * \sqrt{1 - \frac{(0.7c)^2}{c^2}} = 7.14 m$

For the case of spaceship A as observed by spaceship B:

$L = 10 m * \sqrt{1 - \frac{(0.94c)^2}{c^2}} = 3.12 m$

The time dilation equation is:

$T = \frac{T0}{\sqrt{1-\frac{v^2}{c^2}}}$

For the case of the event as observed by you:

$\frac{1 s}{\sqrt{1-\frac{(0.7c)^2}{c^2}}} = 1.40 s$

For the case of the event as observed by spaceship B:

$\frac{1 s}{\sqrt{1-\frac{(0.94c)^2}{c^2}}} = 2.93 s$

3 0

3 years ago

I didn't get it this

alexgriva [62]

Ans: (a) & (c)

The density of a material is its mass per unit volume. This statement is proof enough to validate (c) as an answer. Now 1cm3 is also equal to 1mL, which makes (c)=(a).

7 0

3 years ago

Read 2 more answers

calculate the acceleration of gravity on the surface of kepler-62e Kepler-62e is an exoplanet that orbits within the habitable z

AnnyKZ [126]

The acceleration of gravity is proportional to the planet's mass, and inversely proportional to the square of the planet's radius.

So on this particular planet, the acceleration of gravity will be

(Earth gravity) x ( 3.57 / 1.61²)

That's (9.81 m/s²) x (1.377) = <em>13.51 m/s²</em>

4 0

3 years ago

A coin rests 11.0 cm from the center of a turntable. The coefficient of static friction between the coin and turntable surface i