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Fed [463]
3 years ago
13

A thin 14.7 m long copper rod in a uniform magnetic field has a mass of 49.0 g. When the rod carries a current of 0.317 A, it fl

oats in the magnetic field. What is the field strength of the magnetic field?
Physics
1 answer:
MatroZZZ [7]3 years ago
3 0
F_B = ILBsin \theta

F force
I current
L length of wire in magnetic field
B magnetic field strength
θ angle between wire and magnetic field

if θ = 90°

B = \frac{F_B}{IL} \\ \\ F_B = F_G = mg \\ \\ B = \frac{mg}{IL} = \frac{0.049* 9.81 }{0.317*14.7}
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