Answer:
Coefficient of dynamic friction= md= 0.09931
Explanation:
To determine the coefficient of dynamic friction we must first match the friction force that is permendicular to the normal force of the block and opposite to the drag force, to the component of the drag force in this same direction. This component on the X axis of the drag force will be:
F= 90N × cos(30°) = 77.9423N
This component on the X axis of the drag force must be equal to the dynamic friction force that is equal to the coefficient of dynamic friction by the normal force of the block weight:
F= md × m × g= 77.9423N
m= mass of the block
md= coefficient of dynamic friction
g= gravity acceleration
F= md × 80kg× 9.81 (m/s²)= 77.9423(kg×m/s²)
md= (77.9423(kg×m/s²) / 784.8 (kg×m/s²)) = 0.09931
Answer:
Q = 160.36[kJ], is the heat lost.
Explanation:
This is a thermodynamic problem where we can find the latent heat of vaporization, at a constant temperature of 100 [°C].
We know that for steam at 100[C], the enthalpy is
![h_{gas} = 2675.6[kJ/kg]](https://tex.z-dn.net/?f=h_%7Bgas%7D%20%3D%202675.6%5BkJ%2Fkg%5D)
For liquid water at 100[C], the enthalpy is
![h_{water} = 419.17[kJ/kg]](https://tex.z-dn.net/?f=h_%7Bwater%7D%20%3D%20419.17%5BkJ%2Fkg%5D)
Therefore
![h_{g-w} = 2675.6-419.17 = 2256.43[\frac{kJ}{kg} ]](https://tex.z-dn.net/?f=h_%7Bg-w%7D%20%3D%202675.6-419.17%20%3D%202256.43%5B%5Cfrac%7BkJ%7D%7Bkg%7D%20%5D)
The amout of heat is given by:
![Q=h_{g-w}*m\\ where:\\m = mass = 0.07107[kg] = 71.01[g]\\Q = heat [kJ]\\Q =2256.43*0.07107\\Q=160.36[kJ]](https://tex.z-dn.net/?f=Q%3Dh_%7Bg-w%7D%2Am%5C%5C%20where%3A%5C%5Cm%20%3D%20mass%20%3D%200.07107%5Bkg%5D%20%3D%2071.01%5Bg%5D%5C%5CQ%20%3D%20heat%20%5BkJ%5D%5C%5CQ%20%3D2256.43%2A0.07107%5C%5CQ%3D160.36%5BkJ%5D)
Answer: Distance is the actual position traveled by an object. Displacement is the shortest distance covered by the object.
Explanation:
Distance is the actual length covered by an object from one position to another. It is a scalar quantity. It cannot be negative.
Displacement is the shortest distance covered by the object. The displacement can be calculated by subtracting initial distance from the final distance. It is vector quantity. The displacement covered by an object can be zero, negative and positive.
Suppose, the boy travels from home to school then come back to his home. The distance between from his home to his school is 3 km.
In this case, the boy covers the total distance from home to school then to home is 6 km. But the displacement is zero because he comes to same position.
Explanation:
wait I will give it ur answer
Answer:
The expression for the time taken by an object to move with a speed at some distance is,
t=<u> </u><u>d</u><u>/</u><u>v</u>
Here, t is the time taken by the opponent to react, d is the length of the court, andis the speed of the ball.
Explanation:
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