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alexgriva [62]
2 years ago
8

A car was moving a 14 m/s. After 30 seconds, it’s speed increased to 20 m/s. What was its acceleration during this time?

Physics
2 answers:
Anuta_ua [19.1K]2 years ago
5 0

Answer:

acceleration = 0.2 m/s/s

Explanation:

initial velocity u = 14

final velocity v = 20

time = 30

acceleration = ?

v = u + at

20 = 14 + 30a

30a = 6

a = 0.2 m/s/s

Alexeev081 [22]2 years ago
4 0

Answer:

For the aceleration we have:

V = Vi + a * t

Being:

V = 20 m/s

Vi = 14 m/s

a = ?

t = 30 s

Then, lets replace acording the formula:

20 m/s = 14 m/s + a * 30 s

Clear "a":

a = (20 m/s - 14 m/s) / 30 s

a = (6 m/s) / 30 s

a = 0,2 m/s²

The aceleration of the car is <u>0,2 meters per second squared.</u>

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Lostsunrise [7]

Answer:

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F₂₁ is the vector force on q₁ due to q₂

K is the coulomb's constant = 8.99 X 10⁹ Nm²/C²

r₂₁ is the unit vector

|r₂₁| is the magnitude of the unit vector

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r₂₁ = [(9-5)i +(7.4-(-4))j] = (4i + 11.5j)

|r₂₁| = \sqrt{(4^2)+(11.5^2)} = \sqrt{148.25}

(|r₂₁|)² = 148.25

F_2_1=\frac{K|q_1|q_2|}{r^2}.\frac{r_2_1}{|r_2_1|} = \frac{8.99X10^9(14X10^{-6})(60X10^{-6})}{148.25}.\frac{(4i + 11.5j)}{\sqrt{148.25} }

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Therefore, the force on q₁ due to q₂ is (0.00973i + 0.02798j) N

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A flow is isentropically expanded to supersonic speeds in a convergent-divergent nozzle. The reservoir and exit pressures are 1.
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Answer:

Ae/A* = 1.115

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