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2 years ago

A car was moving a 14 m/s. After 30 seconds, it’s speed increased to 20 m/s. What was its acceleration during this time?

Physics

2 answers:

Anuta_ua [19.1K]2 years ago

5 0

Answer:

acceleration = 0.2 m/s/s

Explanation:

initial velocity u = 14

final velocity v = 20

time = 30

acceleration = ?

v = u + at

20 = 14 + 30a

30a = 6

a = 0.2 m/s/s

Alexeev081 [22]2 years ago

4 0

Answer:

For the aceleration we have:

V = Vi + a * t

Being:

V = 20 m/s

Vi = 14 m/s

a = ?

t = 30 s

Then, lets replace acording the formula:

20 m/s = 14 m/s + a * 30 s

Clear "a":

a = (20 m/s - 14 m/s) / 30 s

a = (6 m/s) / 30 s

a = 0,2 m/s²

The aceleration of the car is <u>0,2 meters per second squared.</u>

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2 years ago

A 4.0 kg shot put is thrown with 30 N of force. What is its acceleration?

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7.5 m/s

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3 years ago

Predict using Boyle's law, what will happen to a balloon that an ocean diver takes to a pressure of 202 kPa.

kobusy [5.1K]

The volume of the balloon will halve

Explanation:

Boyle's law states that for an ideal gas kept at constant temperature, the pressure of the gas is proportional to its volume. Mathematically,

$pV=const.$

where

p is the gas pressure

V is the volume

The equation can also be rewritten as

$p_1 V_1 = p_2 V_2$

And if we apply it to the gas inside the balloon in this problem (assuming its temperature is constant), we have:

$p_1 = 101 kPa$ is the initial pressure at sea level (the atmospheric pressure)

$V_1$ is the initial volume

$p_2 = 202 kPa$ is the final pressure

$V_2$ is the final volume

Substituting into the equation, we find:

$V_2 = \frac{p_1 V_1}{p_2}=\frac{(101)V_1}{202}=\frac{V_1}{2}$

Which means that the volume of the balloon will halve.

Learn more about ideal gases:

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3 years ago

A muon has a rest mass energy of 105.7 MeV, and it decays into an electron and a massless particle. If all the lost mass is conv

sergeinik [125]

Answer:

The electron’s velocity is 0.9999 c m/s.

Explanation:

Given that,

Rest mass energy of muon = 105.7 MeV

We know the rest mass of electron = 0.511 Mev

We need to calculate the value of γ

Using formula of energy

$K_{rel}=(\gamma-1)mc^2$

$\dfrac{K_{rel}}{mc^2}=\gamma-1$

Put the value into the formula

$\gamma=\dfrac{105.7}{0.511}+1$

$\gamma=208$

We need to calculate the electron’s velocity

Using formula of velocity

$\gamma=\dfrac{1}{\sqrt{1-(\dfrac{v}{c})^2}}$

$\gamma^2=\dfrac{1}{1-\dfrac{v^2}{c^2}}$

$\gamma^2-\gamma^2\times\dfrac{v^2}{c^2}=1$

$v^2=\dfrac{1-\gamma^2}{-\gamma^2}\times c^2$

Put the value into the formula

$v^2=\dfrac{1-(208)^2}{-208^2}\times c^2$

$v=c\sqrt{\dfrac{1-(208)^2}{-208^2}}$

$v=0.9999 c\ m/s$

Hence, The electron’s velocity is 0.9999 c m/s.

6 0

3 years ago

On the asteroid Cere, the acceleration due to gravity is about 0.27 m/s^2. How long would it take a ball to fall to the ground i

KiRa [710]

Answer:

F. 25.82 s

Explanation:

Given:

Δy = 90 m

v₀ = 0 m/s

a = 0.27 m/s²

Find: t

Δy = v₀ t + ½ at²

90 m = (0 m/s) t + ½ (0.27 m/s²) t²

t = 25.82 s

7 0

3 years ago