Suppose the number is x, its reciprocal is 1/x
x+1/x=13/6
(x^2+1)/x=13/6
6(x^2+1)=13x
6x^2-13x+6=0
(3x-2)(2x-3)=0
x=2/3 or x=3/2
Answer:
Choice D
Step-by-step explanation:
For this one I would find if the point lands on the line.
<em><u>Choice A:</u></em>
What we have to do is to plug in -4 for x and 4 for y.

The point is not on this line so this cannot be it.
<em><u>Choice B:</u></em>
We pug what we know again.

The point is not on this line so it can't be it.
<em><u>Choice C:</u></em>
We pug in what we know again.

The point is not on this line so it can't be it.
The next one has to be it, but we'll check it just in case.
<em><u>Choice D:</u></em>
We plug in what we know again.

The point is on this line so this is the line.
Answer:
(c) III
Step-by-step explanation:
If you simplify the equations and the left side is identical to the right side, then there are an infinite number of solutions: the equation is true for all values of x.
Another way to simplify the equation is to subtract the right side from both sides. If that simplifies to 0 = 0, then there are an infinite number of solutions.
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<h3>I. </h3>
2x -6 -6x = 2 -4x . . . . eliminate parentheses
-4x -6 = -4x +2 . . . . no solutions (no value of x makes this true)
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<h3>II.</h3>
x +2 = 15x +10 +2x . . . . eliminate parentheses
x +2 = 17x +10 . . . . one solution (x=-1/2)
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<h3>III.</h3>
4 +6x = 6x +4 . . . . eliminate parentheses
6x +4 = 6x +4 . . . . infinite solutions
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<h3>IV.</h3>
6x +24 = 2x -4 . . . . eliminate parentheses; one solution (x=-7)
Answer:

Step-by-step explanation:

