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katovenus [111]
2 years ago
6

How does Shakespeare create an immediate mood of sadness around Romeo

Mathematics
1 answer:
Ber [7]2 years ago
6 0

Answer:

Shakespeare creates an immediate mood of sadness around Romeo because he said sad hours go by slow. also, he talks to benvolio about how sad he is

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The sum of a number and its reciprocal is 13/6. find the number
iris [78.8K]
Suppose the number is x, its reciprocal is 1/x
x+1/x=13/6
(x^2+1)/x=13/6
6(x^2+1)=13x
6x^2-13x+6=0
(3x-2)(2x-3)=0
x=2/3 or x=3/2
6 0
3 years ago
14389+4309 what is it
kow [346]
The answer is 18,698 :)

8 0
3 years ago
Read 2 more answers
PLEASE HELP WILL GIVE BRAINLIEST.
kari74 [83]

Answer:

Choice D

Step-by-step explanation:

For this one I would find if the point lands on the line.

<em><u>Choice A:</u></em>

What we have to do is to plug in -4 for x and 4 for y.

y=2x+10\\(4)=2(-4)+10\\4=-8+10\\4\ne2

The point is not on this line so this cannot be it.

<em><u>Choice B:</u></em>

We pug what we know again.

y=\frac{1}{3}x+1\\(4)=\frac{1}{3}(-4)+1\\(4)=-\frac{4}{3}+1\\4\ne-\frac{1}{3}

The point is not on this line so it can't be it.

<em><u>Choice C:</u></em>

We pug in what we know again.

y=3x-9\\(4)=3(-4)-9\\(4)=-12-9\\4\ne-21

The point is not on this line so it can't be it.

The next one has to be it, but we'll check it just in case.

<em><u>Choice D:</u></em>

We plug in what we know again.

y= \frac{1}{2}x+6\\(4)=\frac{1}{2}(-4)+6\\(4)=-2+6\\4=4

The point is on this line so this is the line.

3 0
3 years ago
What is the answer to this?
Dmitry [639]

Answer:

  (c)  III

Step-by-step explanation:

If you simplify the equations and the left side is identical to the right side, then there are an infinite number of solutions: the equation is true for all values of x.

Another way to simplify the equation is to subtract the right side from both sides. If that simplifies to 0 = 0, then there are an infinite number of solutions.

__

<h3>I. </h3>

  2x -6 -6x = 2 -4x . . . . eliminate parentheses

  -4x -6 = -4x +2 . . . . no solutions (no value of x makes this true)

__

<h3>II.</h3>

  x +2 = 15x +10 +2x . . . . eliminate parentheses

  x +2 = 17x +10 . . . . one solution (x=-1/2)

__

<h3>III.</h3>

  4 +6x = 6x +4 . . . . eliminate parentheses

  6x +4 = 6x +4 . . . . infinite solutions

__

<h3>IV.</h3>

  6x +24 = 2x -4 . . . . eliminate parentheses; one solution (x=-7)

8 0
2 years ago
Please please help me
Gekata [30.6K]

Answer:

\large\boxed{\dfrac{\boxed{8}}{81}}

Step-by-step explanation:

\text{If}\ a_1,\ a_2,\ a_3,\ a_4,\ ...,\ a_n\ \text{is the geometric sequence, then}\\\\\dfrac{a_2}{a_1}=\dfrac{a_3}{a_2}=\dfrac{a_4}{a_3}=...=\dfrac{a_n}{a_{n-1}}=constant=r-\text{common ration}.\\\\\text{We have}\ \dfrac{1}{2},\ \dfrac{1}{3},\ \dfrac{2}{9},\ \dfrac{4}{27},\ ...\\\\\dfrac{\frac{1}{3}}{\frac{1}{2}}=\dfrac{1}{3}\cdot\dfrac{2}{1}=\dfrac{2}{3}\\\\\dfrac{\frac{2}{9}}{\frac{1}{3}}=\dfrac{2}{9}\cdot\dfrac{3}{1}=\dfrac{2}{3}\\\\\dfrac{\frac{4}{27}}{\frac{2}{9}}=\dfrac{4}{27}\cdot\dfrac{9}{2}=\dfrac{2}{3}

\bold{CORRECT}\\\\\dfrac{x}{\frac{4}{27}}=\dfrac{2}{3}\qquad\text{multiply both sides by}\ \dfrac{4}{27}\\\\x=\dfrac{2}{3}\cdot\dfrac{4}{27}\\\\x=\dfrac{8}{81}

8 0
3 years ago
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