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3 years ago

1,632 rounded by the nearest ten is ____

Physics

2 answers:

maksim [4K]3 years ago

8 0

Answer:

1,632 rounded by the nearest ten is 1630

783 rounded by the nearest hundred is 800

43,761 rounded by the nearest thousand is 44,00

Explanation:

Anna71 [15]3 years ago

4 0

1,632 rounded by the nearest ten is 1,630 because 2 is not greater or equal to 5.
783 rounded by the nearest hundred is 800 because 83 is greater than or equal to 50.
43,761 rounded by the nearest thousand is 44,00 because 761 is greater than or equal to 500.

Step-by-Step
If it is round by the nearest 10, there is one 0 so you only count the last number. For example, 437. The last number is 7, and we are only using 7 in this case because there is only 1 zero in 10. Next step is see if 7 is greater than or equal to 5. We can see that it is, so we will round up in this case making 437 change into 440. Another example, 11,439 rounded to the nearest 1,000 th. Well there is 3, zeros so we will count the last three numbers only. Is 439 greater than or equal to 500? No. So we will round down in this case and the answer will be 11,000. Hope this helps you to understand :)

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maksim [4K]

Answer:

The work is -67.76 J

Explanation:

The law of conservation of energy is considered one of one of the fundamental laws of physics and states that the total energy of an isolated system remains constant. except when it is transformed into other types of energy.

This is summed up in the principle that energy can neither be created nor destroyed in the universe, only transformed into other forms of energy.

In this case you must calculate the loss of kinetic energy. This loss is actually the work done against the resistive force in the air. Friction is the only force other than gravity that acts on the ball.

So, the loss of kinetic energy is $\frac{1}{2} *m*(vf^{2} -vi^{2} )$

You know:

mass=m=0.22 kg
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Final velocity of the ball: $vf= 15 \frac{m}{s}$

Replacing:

$\frac{1}{2} *0.22 kg*(15^{2} -29^{2} )$ = -67.76 J

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3 years ago

Since entropy is about how energy is shared, it is important to be able to identify places where energy can be put, or degrees o

Fiesta28 [93]

Answer:

Please see answer in explanation

Explanation:

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3 years ago

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Tasya [4]

Answer:

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Explanation:

For this exercise we will use the concepts of mechanical energy, for which we define energy n the initial point and the point of average height and / 2

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Em₀ = m₁ g y₁ + m₂ g y₂

Let's place the reference system at the point where the mass m1 is

y₁ = 0

y₂ = y

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End point, at height yf = y / 2

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How energy is conserved

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3 years ago

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777dan777 [17]

Answer:

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Explanation:

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