Answer:
α = 0.0135 rad/s²
Explanation:
given,
t = 133 min = 133 x 60 = 7980 s
angular speed varies from 570 rpm to 1600 rpm
now,
570 rpm = ![570 \times \dfrac{2\pi}{60}](https://tex.z-dn.net/?f=570%20%5Ctimes%20%5Cdfrac%7B2%5Cpi%7D%7B60%7D)
= 59.69 rad/s
1600 rpm = = ![570 \times \dfrac{2\pi}{60}](https://tex.z-dn.net/?f=570%20%5Ctimes%20%5Cdfrac%7B2%5Cpi%7D%7B60%7D)
= 167.6 rad/s
using equation of rotational motion
ωf = ωi + αt
167.6 = 59.7 + α x 7980
α x 7980 = 107.9
α = 0.0135 rad/s²
Answer: 24.5 cm
Explanation:
Given
Force constant of spring, k = 40 N/m
Diameter of spring, d = 5.1 cm = 0.051 m
Mass of cylinder, m = 1.5 kg
Let us assume that the cylinder is hanging in such a way that the circular end is parallel with the water. Also, we assume that the tank water level is not materially affected by the displacement of the cylinder while the cylinder sinks. The water is fresh and as we all know, the density of water is 1000 kg/m³
To solve this, we assume x to be the spring extension and it's equivalent sinking distance(in meters). We then apply the formula,
mg = kx + ρgAx
mg = x(k + ρgA)
x = mg / (k + ρgA), where
A = πd²/4
A = (3.142 * 0.051²)/4
A = 0.0082 / 4
A = 0.00205 m²
x = 1.5 * 9.81 / [40 + (1000 * 9.81 * 0.00205)]
x = 14.715 / (40 + 20.1105)
x = 14.715 / 60.1105
x = 0.245 m
or 24.5 cm of stretch or sinking
Answer:
let current flow be x
Explanation:
than we know potential difference = energy supply / charge then 120 = 10 /x then x=12 therefore pd = 12 v
Answer:
A little over a second
Explanation:
gravity pulls down on objects at a speed of 9.8 meters a second
The object is in free fall when and only when it is being affected by gravity alone. It is not being influenced by a significant amount of air resistance will always be in free fall. F(net)/m = acceleration