Graph x <3 Please help me

WORTH 100 POINTS

guajiro [1.7K]

Answer:

The problem does not work.

Step-by-step explanation:

The plane with speed of 31 mph will cover 640 miles in $\frac{640}{31} = 20.64$ hours.

Now, it burns 5 gallons of gas every 3 minutes i.e. 0.05 hours.

So, it will burn in 20.64 hours $\frac{5 \times 20.64}{0.05} = 2064$ gallons.

Now, the helicopter with speed of 45 mph will cover 640 miles in $\frac{640}{45} = 14.22$ hours.

Now, it burns 7 gallons of gas every 5 minutes i.e. 0.083 hours.

So, it will burn in 14.22 hours $\frac{7 \times 14.22}{0.083} = 1194.48$ gallons.

But both of them starts with only 80 gallons of fuel.

Therefore, the problem does not work. (Answer)

4 0

3 years ago

What is the first significant figure of 13822?

deff fn [24]

Answer:

1

Step-by-step explanation:

The rules for significant figures are:

Non-zero digits are always significant.
Zeros between significant digits are also significant.
Trailing zeros are significant only after a decimal point.

In 13822, all of the digits are non-zero. So the first significant figure is 1.

3 0

3 years ago

_1.Straighthedge _2.line segment _3.parallel line _4.angle _5.angle bisector

AlexFokin [52]

Answer:):Step-by-step explanation:

sagutan ko sana kaso mahirap

7 0

3 years ago

What is the sum of the polynomials

Ratling [72]

17m-12n-1+ 4-13m-12n
Add like terms-- (17m-13m= 4m) (-12n-12n= -24n )(4-1=3)
Then put them together to get your answer.
So the answer is 4m -24n+3

7 0

3 years ago

Read 2 more answers

I need to know how to do the whole thing and understand it.

patriot [66]

We are given the data on the number of candies handed by neighborhood A and neighborhood B.

Let us first find the mean and variance of each neighborhood.

Mean:

$\bar{x}_A=\frac{\sum x}{N_1}=\frac{12}{6}=2$ $\bar{x}_B=\frac{\sum x}{N_2}=\frac{20}{6}=3.33$

Variance:

$s_A^2=\frac{\sum x^2}{N_1}-\bar{x}_A^2=\frac{28}{6}-2^2=0.667$ $s_B^2=\frac{\sum x^2}{N_2}-\bar{x}_B^2=\frac{80}{6}-3.33^2=2.244$

A. Null hypothesis:

The null hypothesis is that there is no difference in the mean number of candies handed out by neighborhoods A and B.

$H_0:\;\mu_A=\mu_B$

Research hypothesis:

The research hypothesis is that the mean number of candies handed out by neighborhood A is more than neighborhood B.

$H_a:\;\mu_A>\mu_B$

Test statistic (t):

The test statistic of a two-sample t-test is given by

$t=\frac{\bar{x}_A-\bar{x}_B}{s_p}$

Where sp is the pooled standard deviation given by

$\begin{gathered} s_p=\sqrt{\frac{N_1s_1^2+N_2s_2^2}{N_1+N_2-2}(\frac{N_1+N_2}{N_1\cdot N_2}}) \\ s_p=\sqrt{\frac{6\cdot0.667+6\cdot2.244}{6+6-2}(\frac{6+6}{6\cdot6})} \\ s_p=0.763 \end{gathered}$ $t=\frac{2-3.33}{0.763}=-1.74$

So, the test statistic is -1.74

Critical t:

Degree of freedom = N1 + N2 - 2 = 6+6-2 = 10

Level of significance = 0.05

The right-tailed critical value for α = 0.05 and df = 10 is found to be 1.81

Critical t = 1.81

We will reject the null hypothesis because the calculated t-value is less than the critical value.

Interpretation:

This means that we do not have enough evidence to conclude that neighborhood A gives out more candies than neighborhood B.

6 0

1 year ago