Question

Each box weighs 10lb. The coefficient of static friction between box A and box B is 0.24, and the coefficient of static friction between box B and the inclined surface is 0.3. What is the largest angle for which box B will not slip​

Answer 1

The largest angle for which box B will not slip​ is 16.7⁰.

The given parameters:

• weight of box, W = 10 lb
• coefficient of static friction between box A and box B, $\mu_s_1$ = 0.24
• coefficient of static friction between box B and the inclined surface, $\mu_s_2$ = 0.3

The frictional force between box A and box B is calculated as;

$F_f_1= \mu_s_1 (mg)$

The frictional force between box B and inclined surface is calculated as;

$F_f = \mu_s_2 (2mg) cos(\theta)$

The net force on the boxes that results in no movement is calculated as;

$(2mg) sin(\theta) - F_f= 0\\\\(2mg) sin(\theta) = F_f\\\\(2mg) sin(\theta) = \ \mu_s_2 (2mg) cos(\theta)\\\\ sin(\theta) = \mu_s_2 cos(\theta)\\\\\mu_s_2 = \frac{sin(\theta)}{cos(\theta)} \\\\\mu_s_2 = tan(\theta)\\\\\theta = tan^{-1} (\mu_s_2)\\\\\theta = tan^{-1} (0.3)\\\\\theta = 16.7 \ ^ 0$

Thus, the largest angle for which box B will not slip​ is 16.7⁰.

Learn more about coefficient of static friction here: brainly.com/question/25050131