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Phoenix [80]
3 years ago
15

One of the checks that you could do for problem 1) would be to check the output resistance of the Wheatstone bridge to make sure

the bridge is not damaged. With no power connected to the bridge, you connect anOhmmeter to the outputpins. If each arm(branch)of the Wheatstone Bridge is 350Ω, what should the resistance read and why? (Draw the circuit and show your calculations.)
Physics
1 answer:
Ray Of Light [21]3 years ago
6 0

Answer:

Explanation:

Let the four resistances of th wheat stone bridge is

P, Q, R and S and the value of each is 350 ohm.

Here, P and Q are in series.

R' = P + Q = 350 + 350 = 700 ohm

Then R and S are in series

R' = R + S = 350 + 350 = 700 ohm

Now R' and R'' are in parallel.

So, the equivalent resistance is

Req = R' x R'' / ( R' + R'')

Req = 700 / 2 = 350 ohm

Thus, the reading of ohmmeter is 350 ohm.

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