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Phoenix [80]
3 years ago
15

One of the checks that you could do for problem 1) would be to check the output resistance of the Wheatstone bridge to make sure

the bridge is not damaged. With no power connected to the bridge, you connect anOhmmeter to the outputpins. If each arm(branch)of the Wheatstone Bridge is 350Ω, what should the resistance read and why? (Draw the circuit and show your calculations.)
Physics
1 answer:
Ray Of Light [21]3 years ago
6 0

Answer:

Explanation:

Let the four resistances of th wheat stone bridge is

P, Q, R and S and the value of each is 350 ohm.

Here, P and Q are in series.

R' = P + Q = 350 + 350 = 700 ohm

Then R and S are in series

R' = R + S = 350 + 350 = 700 ohm

Now R' and R'' are in parallel.

So, the equivalent resistance is

Req = R' x R'' / ( R' + R'')

Req = 700 / 2 = 350 ohm

Thus, the reading of ohmmeter is 350 ohm.

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Answer:

357.6g

Explanation:

Given parameters:

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To find the mass;

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Now insert the parameters and solve;

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Answer:

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The energy of the wave depends on both the amplitude and the frequency. If the energy of each wavelength is a discrete packet of energy, a high-frequency wave will deliver more of these packets per unit time than a low-frequency wave. In summary, the longer the wavelength, the lower the energy to ionise.

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