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Ivanshal [37]
2 years ago
9

List the three properties of a thermometer​

Physics
1 answer:
Rashid [163]2 years ago
4 0

Answer:

Property Thermometer

Volume expansion of a gas Gas thermometer

Volume expansion of a liquid Laboratory or clinical thermometer

Volume expansion of a solid Bi-metallic strip thermometer

Pressure change of a fixed mass of gas Constant – volume gas thermometer

Changes in e.m.f. Thermocouple

Changes in electrical resistance Resistance thermometer or thermistor

Changes in wavelength Pyrometer

Changes in magnetic flux or sound energy Magnetic or sonic thermometer

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Please help on this one?
kupik [55]

Answer: A)30V. First find the current of the circuit. I=V/R(total resistance). So I=60/120=0.5. Now to find voltage drop in R3 use ohms law as given. V(of 3)=(0.5)(60)=30V

7 0
2 years ago
A mass m attached to a horizontal massless spring with spring constant k, is set into simple harmonic motion. its maximum displa
Lesechka [4]
At the point of maximum displacement (a), the elastic potential energy of the spring is maximum:
U_i= \frac{1}{2} ka^2
while the kinetic energy is zero, because at the maximum displacement the mass is stationary, so its velocity is zero:
K_i =0
And the total energy of the system is
E_i = U_i+K= \frac{1}{2}ka^2

Viceversa, when the mass reaches the equilibrium position, the elastic potential energy is zero because the displacement x is zero:
U_f = 0
while the mass is moving at speed v, and therefore the kinetic energy is
K_f =  \frac{1}{2} mv^2
And the total energy is
E_f = U_f + K_f =  \frac{1}{2} mv^2

For the law of conservation of energy, the total energy must be conserved, therefore E_i = E_f. So we  can write
\frac{1}{2} ka^2 =  \frac{1}{2}mv^2
that we can solve to find an expression for v:
v= \sqrt{ \frac{ka^2}{m} }
6 0
3 years ago
An LR circuit contains an ideal 60-V battery, a 42-H inductor having no resistance, a 24-ΩΩ resistor, and a switch S, all in ser
s2008m [1.1K]

Answer:

1.6 s

Explanation:

To find the time in which the potential difference of the inductor reaches 24V you use the following formula:

V_L=V_oe^{-\frac{Rt}{L}}

V_o: initial voltage = 60V

R: resistance = 24-Ω

L: inductance = 42H

V_L: final voltage = 24 V

You first use properties of the logarithms to get time t, next, replace the values of the parameter:

\frac{V_L}{V_o}=e^{-\frac{Rt}{L}}\\\\ln(\frac{V_L}{V_o})=-\frac{Rt}{L}\\\\t=-\frac{L}{R}ln(\frac{V_L}{V_o})\\\\t=-\frac{42H}{24\Omega}ln(\frac{24V}{60V})=1.6s

hence, after 1.6s the inductor will have a potential difference of 24V

3 0
3 years ago
Nahzvsbsnsnsmsskskssks
prisoha [69]

Answer:

some one might report you

Explanation:

3 0
3 years ago
Read 2 more answers
A 3.6kg mass is accelerated at 2.5m/s. Calculate the resultant force<br> acting on it.
AleksandrR [38]
Force = mass*acceleration so
3.6*2.5 =9 Newtons
5 0
2 years ago
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