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taurus [48]
2 years ago
7

Debbie's bank offers an online bill pay service. For this, the bank charges $2.25 per month plus $0.10 per bill paid using the s

ervice. How many bills does she pay each month if the charges are always between $3.50 and $5.00? (Note: She is not allowed to pay part of a bill.)
Mathematics
1 answer:
Andru [333]2 years ago
7 0

Based on the information given, the number of bills will have to be between 13 and 28 every month.

<h3>Solving equations</h3>

Let the number of bills be represented by x.

Therefore, the equation to solve the question will be:

2.25 + (0.10 × x) = 3.50

2.25 + 0.10x = 3.50

0.10x = 3.50 - 2.25

0.10x = 1.25

x = 1.25/0.10 = 12.5 = 13

Also, 2.25 + 0.10x = 5.00

0.10x = 5.00 - 2.25

0.10x = 2.75

x = 27.5 = 28

Therefore, the number of bills will be between 13 and 28 every month.

Learn more about equations on:

brainly.com/question/13763238

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Step-by-step explanation:

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Find g(x), where g(x) is the translation 9 units up of f(x) = |x|.
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g(x) is the translation 9 units up of f(x) = |x|

g(x)=1|x-0|+9

Given :

The function f(x)=|x|

we need to translate f(x) , 9 units up to get g(x)

g(x) is the translation 9 units up of f(x)

when graph of f(x) is translated 9 units up , then we add 9 at the end

If f(x)=|x| is translated 'a' units up then its  becomes |x|+a

g(x) is the translation 9 units up of f(x) = |x|

So , g(x)=|x|+9

Write the answer in the given form a|x-h|+k

g(x)=1|x-0|+9

Learn more :  brainly.com/question/21960107

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AHarris Interactive survey for InterContinental Hotels &amp; Resorts asked respondents, "When traveling internationally, do you
Sauron [17]

Answer:

a) There is a 27.89% probability that two will stick with their tour group.

b) There is a 41.81% that in at least two will stick with their tour group.

c) There is a 7.33% probability that none will stick with their tour group.

Step-by-step explanation:

For each responders, this question can only have two outcomes. Either they stick with their tour group, or they don't. So this means that we can solve this problem as binomial distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

For these problems

The survey found that 23% of the respondents stick with their tour group, so \pi = 0.23.

a. In a sample of six international travelers, what is the probability that two will stick with their tour group?

The sample has six travelers, so n = 6.

We want P(X = 2).

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 2) = C_{6,2}.(0.23)^{2}.(0.77)^{4} = 0.2789

There is a 27.89% probability that two will stick with their tour group.

b. In a sample of six international travelers, what is the probability that at least two will stick with their tour group?

Either less than two stick with their groups, or at least two do. The sum of these probabilities is decimal 1.

So

P(X < 2) + P(X \geq 2) = 1

P(X \geq 2) = 1 - P(X < 2)

In which

P(X < 2) = P(X = 0) + P(X = 1)

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 0) = C_{6,0}.(0.23)^{0}.(0.77)^{6} = 0.2084

P(X = 1) = C_{6,1}.(0.23)^{1}.(0.77)^{5} = 0.3735

-----

P(X < 2) = P(X = 0) + P(X = 1) = 0.2084 + 0.3735 = 0.5819

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.5819 = 0.4181

There is a 41.81% that in at least two will stick with their tour group.

c. In a sample of 10 international travelers, what is the probability that none will stick with the tour group?

Now our sample has 10 travelers, so n = 10.

We want to find P(X = 0)

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 0) = C_{10,0}.(0.23)^{0}.(0.77)^{10} = 0.0733

There is a 7.33% probability that none will stick with their tour group.

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4 years ago
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