Explanation:
The given data is as follows.
q = 6.0 nC =
inner radius (r) = 1.0 cm = 0.01 m (as 1 cm = 100 m)
So, there will be same charge on the inner surface as the charge enclosed with an opposite sign.
Formula to calculate the charge density is as follows.
.......... (1)
Since, area of the sphere is as follows.
A = ........... (2)
Hence, substituting equation (2) in equation (1) as follows.
=
=
or, = 4.77
Thus, we can conclude that the resulting charge density on the inner surface of the conducting sphere is 4.77 .
The net force is determined is basically who is pushing harder in a specific direction.Like since there bith pushing in the same direction the net force is in the direction that they are pushing.
current . . . flow of electric charges
voltage . . . stored potential energy at the source of a circuit
resistance . . . opposition to the flow of electric current
arrowRight . . . a button on the computer keyboard that causes the cursor to move to the right on the screen when pushed
arrowRight . . . a button on the computer keyboard that causes the cursor to move to the right on the screen when pushed
arrowRight . . . a button on the computer keyboard that causes the cursor to move to the right on the screen when pushed
Children with low self efficacy will take a longer time to achieve their targets whereas those with high self effficacy will be more likely to find success easily
Given: Force=8000N
displacement= 15 m
W=denotes Work
W= f × d
Substitute Values:
W = 8000 N × 15 m
= 120, 000 Nm
So, the elevator is doing 120, 000 Joule.
( Joule is the SI unit of work)