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ludmilkaskok [199]
2 years ago
15

Calculate the oxidation number for carbon in CH4

Chemistry
1 answer:
Maksim231197 [3]2 years ago
8 0

Answer:

+4

Explanation:

Oxidation number of neutral compound is 0

Oxidation number of hydrogen in methane is -1

C + (-1×4) = 0

C - 4 = 0

C = 4

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When 78.6 g of urea CH4N2O are dissolved in 700. g of a certain mystery liquid X, the freezing point of the solution is 4.9 °C
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When 78.6 g of sodium chloride are dissolved in the same mass of X, the freezing point of the solution is 8.5°C lower than the freezing point of pure X.

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ΔT = i*Kf*m

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⇒with Kf =the freezing point depression consant of X = TO BE DETERMINED

⇒with m = the molality of urea solution = 1.87 molal

4.9 °C = 1 * Kf * 1.87 molal

Kf == 4.9 / 1.87

Kf = 2.62 °C/m

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ΔT = i*Kf*m

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8.5 °C = i * 2.62 °C/m * 1.92 m

i = 8.5 / (2.62 * 1.92)

i = 1.69

The van't Hoff factor of NaCl in liquid X is 1.69

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