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DanielleElmas [232]
3 years ago
6

Which type of chemical model shows the bond angle and bond length between atoms and compounds?

Chemistry
1 answer:
ELEN [110]3 years ago
8 0

A molecular structure also shows the bond angle and the Bond length between different atoms in a compound.

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Type the correct answer in the box. Use numerals instead of words.
Murrr4er [49]

Answer:

The amount of energy transferred to the coin is 28.5 joules.







Explanation:

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#TheWizzer

5 0
3 years ago
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I would appreciate your help! Due today! ( I don't know if this is even chemistry)
Vinil7 [7]

Answer:

6+69

Explanation:

6 0
3 years ago
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Use the equations below to calculate the enthalpy of formation for propane gas, C3H8, from its elements, hydrogen gas and solid
IceJOKER [234]

Answer: I got -4542.9kg/mol

Explanation:

8 0
3 years ago
A 33.153 mg sample of a chemical known to contain only carbon, hydrogen, sulfur, and oxygen is put into a combustion analysis ap
elena-14-01-66 [18.8K]

Answer:

The empirical formula of the compound = C_4H_8S_1O_1

Explanation:

Mass of carbon dioxide gas = 59.060 mg = 0.059060 g

1 mg = 0.001 g

Moles of carbon dioxide = \frac{0.059060 g}{44 g/mol}=0.0013 mol

Moles of carbon in 0.0013 moles of carbon dioxide gas = 1 × 0.0013 mol = 0.0013 mol

Mass of 0.0013 moles of carbon = 12 g/mol\times 0.0013 mol=0.0156 g

Mass of water = 24.176 mg = 0.024176

Moles of water = \frac{0.024176 g}{18 g/mol}=0.0013 mol

Moles of hydrogen in 0.0013 moles of water = 2 × 0.0013 mol = 0.0026 mol

Mass of 0.0013 moles of hydrogen= 1 g/mol\times 0.0013 mol=0.0013 g

Mass of sulfur dioxide = 20.326 mg = 0.020326 g

Moles of sulfur dioxide = \frac{0.020326 g}{64 g/mol}=0.00032 mol

Moles of sulfur in 0.00032 moles of sulfur dioxide = 1 × 0.00032 mol = 0.00032 mol

Mass of 0.00032 moles of sulfur = 32 g/mol\times 0.00032 mol=0.01024 g

Mass of oxygen in the sample = x

Mass of sample = 33.153 mg = 0.033153 g

0.033153 g = 0.0156  g + 0.0013 g + 0.01024 g + x

x = 0.006013 g

Moles of oxygen = \frac{0.006013 g}{16 g/mol}=0.00038 mol

For empirical formula divide the lowest number of moles of elemnt from all the moles of the all the elements:

Carbon : \frac{0.0013 mol}{0.00032 mol}=4

Hydrogen: \frac{0.0026 mol}{0.00032 mol}=8

Sulfur : \frac{0.00032 mol}{0.00032 mol}=1

Oxygen : \frac{0.00038 mol}{0.00032 mol}=1

The empirical formula of the compound = C_4H_8S_1O_1

8 0
4 years ago
A student calculates the mass of a piece of copper to be 8.3 grams. The actual mass of the copper is 10. grams. What is the perc
jok3333 [9.3K]

<u>Answer:</u>

17%

<u>Explanation:</u>

Mass of a piece of copper calculated by student = 8.3 grams

Actual mass of copper = 10 grams

We know the formula for the percent error:

Percentage error = (| experimental value - actual value | / actual value) * 100

So substituting the given values in the above formula:

Percent error = (|8.3 - 10| / 10) * 100 = (1.7/10) * 100 = 17%

3 0
4 years ago
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