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alexgriva [62]
3 years ago
11

Cookies are sold singly or in packages of 11 or 33 with this packaging how many ways can you buy 66 cookies

Mathematics
1 answer:
ale4655 [162]3 years ago
3 0

Answer:

You can buy 66 cookies in 3 ways.

Step-by-step explanation:

Step 1

Buying only six packages of 11

6*11 = 66

therefore

1st way -----> 6 packages of 11

Step 2

Buying only two packages of 33

2*33 = 66

2nd way -----> 2 packages of 33

Step 3

Buying 1 package of 33 and 3 packages of 11

1*33 + 3*11 = 66.

therefore

You can buy 66 cookies in 3 ways.

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Answer:

$4,500.

Step-by-step explanation:

1 year and 6 months is 18 months, so 250 times 18 is 4,500.

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What categories does the the following number belong in? -17
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Answer:

c.

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2 years ago
Which expression is equivalent to StartFraction 2 a + 1 Over 10 a minus 5 Endfraction divided by StartFraction 10 a Over 4 a squ
const2013 [10]

Answer:

\frac{(2a + 1)^2}{50a}

Step-by-step explanation:

Given

\frac{2a + 1}{10a - 5} / \frac{10a}{4a^2 - 1}

Required

Find the equivalent

We start by changing the / to *

\frac{2a + 1}{10a - 5} / \frac{10a}{4a^2 - 1}

\frac{2a + 1}{10a - 5} * \frac{4a^2 - 1}{10a}

Factorize 10a - 5

\frac{2a + 1}{5(2a - 1)} * \frac{4a^2 - 1}{10a}

Expand 4a² - 1

\frac{2a + 1}{5(2a - 1)} * \frac{(2a)^2 - 1}{10a}

\frac{2a + 1}{5(2a - 1)} * \frac{(2a)^2 - 1^2}{10a}

Express (2a)² - 1² as a difference of two squares

Difference of two squares is such that: a^2- b^2= (a+b)(a-b)

The expression becomes

\frac{2a + 1}{5(2a - 1)} * \frac{(2a - 1)(2a + 1)}{10a}

Combine both fractions to form a single fraction

\frac{(2a + 1)(2a - 1)(2a + 1)}{5(2a - 1)10a}

Divide the numerator and denominator by 2a - 1

\frac{(2a + 1)((2a + 1)}{5*10a}

Simplify the numerator

\frac{(2a + 1)^2}{5*10a}

\frac{(2a + 1)^2}{50a}

Hence,

\frac{2a + 1}{10a - 5} / \frac{10a}{4a^2 - 1} = \frac{(2a + 1)^2}{50a}

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