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2 years ago

Ethanol, CzH5OH, is an organic chemical compound used in medical wipes and most commonly in antibacterial

Chemistry

2 answers:

Vlada [557]2 years ago

6 0

Answer:

13.04 %

Explanation:

First, find the Molecular mass of the individual elements present in the compound.

Carbon = 12

Hydrogen = 1

Oxygen = 16

Then, find the total mass of C₂H₅OH

(12 × 2) + (1 × 5) + 16 + 1 = 46

In order to find the percentage mass of hydrogen, you must take the Molecular mass of hydrogen in the compound, divide it by the Molecular mass of the compound and times that by 100.

% by mass of hydrogen = $\frac{1*6}{46}$ × 100

[it is 1 × 6 because 1 is the mass of hydrogen and there are 6 hydrogen atoms in C₂H₅OH]

% by mass of hydrogen = 13.04 %

Alinara [238K]2 years ago

3 0

Answer:

13.1275%

Explanation:

Molecular formula of ethanol is C2H5OH

Molar mass of ethanol is 46.0684g/mol

Carbon: 24.02g/mol

Hydrogen: 6.05g/mol

Oxygen: 15.99g/mol

Mass percent of hydrogen = 6/46×100 = 13.1275%

Hope this helps, have a great day!

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Nitrogen dioxide is a red-brown gas responsible for the brown color of smog. A container of nitrogen dioxide that is at low pres

____ [38]

Answer:

Initially $1.51\times 10^{-2} moles$ of nitrogen dioxide were in the container .

Explanation:

Volume of the container at low pressure and at room temperature = $V_1=3.4 L$

Number of moles in the container = $n_1$

After more addition of nitrogen gas at the same pressure and temperature.

Volume of the container after addition = $V_2=5.11 L$

Number of moles in the container after addition= $n_2=2.28\times 10^{-2} mol$

Applying Avogadro's law:

$\frac{Volume}{Moles}=constant$ (at constant pressure and temperature)

$\frac{V_1}{n_1}=\frac{V_2}{n_2}$

$n_1=\frac{V_1\times n_2}{V_2}=\frac{3.4 L\times 2.28\times 10^{-2} mol}{5.11 L}$

$n_1=1.51\times 10^{-2} mol$

Initially $1.51\times 10^{-2} moles$ of nitrogen dioxide were in the container .

8 0

3 years ago

When elemental boron, B, is burned in oxygen gas, the product is diboron trioxide. If the diboron trioxide is then reacted with

zalisa [80]

<u>Answer:</u> The chemical equation is written below.

<u>Explanation:</u>

Every balanced chemical equation follows law of conservation of mass.

This law states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form. This also means that total number of individual atoms on reactant side must be equal to the total number of individual atoms on the product side.

The chemical equation for the reaction of elemental boron and oxygen gas follows:

$4B+3O_2\rightarrow 2B_2O_3$