The answer to the question is 0.8055 as the answer should not include units in it.
Molarity (M) = n/v
n = moles of solute
v = liters of solution
According to question
1% solution → 1 gram of solute for 100 milliliters of solution
2% solution → 2 grams of solute for 100 milliliters of solution
6% NaClO solution → 6 grams of NaClO (solute) for 100 milliliters of solution
Molar mass of NaClO = (22.98 + 35.5 + 16)g/mol = 74.48 g/mol
Atomic mass of Na = 22.98 g/mol
Atomic mass of Cl = 35.5 g/mol
Atomic mass of O = 16 g/mol
1 mol NaClO = 74.48 grams NaClO
74.48 grams NaClO = 1 mol NaClO
6 grams NaClO = (1×6) / 74.48 mole = 0.08055 mole
As unit molarity is mole / liter
So 100 milliliters = 0.1 liters
1 liter = 1000 milliliters
100 milliliters = 100/1000 liters = 0.1 liters
Molarity of NaClO = moles of solute (NaClO) / liters of solution or volume of solution
Molarity of NaClO = 0.08055 / 0.1 mole/L = 0.8055 mole/L
As in question it is mentioned that 'Do not type units into your answer'
So, Molarity of NaClO in clorox bleach = 0.8055
Thus we find out the value of molarity of NaClO in Clorox bleach which came out to be 0.8055 as we dont have to give the answer with units.
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