Answer:
3 factors that are required for biodegradation are
a) Appropriate moisture
b) Oxygen supply
c) Stable condition
Explanation:
For biodegradation in a landfill, following conditions are essential –
a) Appropriate moisture
b) Oxygen supply
c) Stable condition
Contrast to above three conditions, the waste in landfill is kept dry, devoid of oxygen supply, and stirred continuously due to which the organic matter mummify instead of decomposing.
The additional volume of HCl which must be added to reach to the equivalence point is 8.33 mL
The moles of HCl which is required to reach the equivalence point can be calculated in the way as follows.
Moles of HCl can be calculated as
Moles of HCl = 0.004 moles of Ca (OH) 2 × 2 moles of HCl / 1 moles of Ca (OH) 2
= 0.008 moles of HCl
The volume of HCl which is required to reach the equivalence point can be calculated in the way given as follows.
Volume of HCl required= 0.008 moles of HCl × 1 L / 0.24 moles of HCl × 1 ml / 10 -³ L
= 33.33 ml
The additional volume of HCl calculated as
Additional volume = required volume – actual volume
= 33.33 mL – 25 mL
= 8 . 33 mL
Thus, we calculated that the additional volume of HCl which must be added to reach to the equivalence point is 8.33 mL.
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Explanation:
Bases have a slippery feel when touched but acids do not have a slippery feel.
- An acid is a substance that interacts with water to produce excess hydroxonium ions, H₃O⁺ in an aqueous solution. Here are some of its properties:
- Their dilute solutions have a sour taste.
- They have a burning effect on the skin and are highly corrosive on metals.
- They have the ability to change the colors of indicators.
- They react with bases to form salt and water only.
Examples of acids are:
Hydrochloric acid HCl
Tetraoxosulphate (VI ) acid H₂SO₄
- A base is a substance that interacts with water to produce excess hydroxide ions, OH⁻ in an aqueous solution.
- They typically have a bitter taste.
- They have a soapy feel
- They are electrolytes
- They also change the color of indicators
Examples are:
Potassium hydroxide KOH
Sodium hydroxide NaOH
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Given:
E = 7.3 × 10–17 Hz
h= 6.63 × 10–34 J•s
Now <em>E = hf</em>
where E is the energy of the photon
h is the Planck's constant
f is the frequency of the photon
Substituting the values in the equation we get
E= 7.3 × 10^-17 × 6.63 × 10^-34
<u>E= 4.8399 × 10^-50 J. </u>
Although it has a negative charge, it will never accept a
H
+
to form
H
2
S
O
4
(sulfuric acid) . That is because sulfuric acid is a strong acid and completely disassociates in water.
Therefore, the sulfate ion (
S
O
2
−
4
) is the conjugate base of
H
S
O
−
4
.