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Airida [17]
3 years ago
14

In an exothermic reaction, chlorine reacts with 2.0200g of hydrogen to form 72.926g of hydrogen chloride gas. how many grams of

chlorine reacted with hydrogen
Chemistry
1 answer:
Artemon [7]3 years ago
4 0

Answer : 70.906 grams of chlorine reacted with hydrogen

Explanation :

Step 1 : Write balanced chemical equation.

The balanced chemical equation for the reaction between hydrogen and chlorine gas is given below.

H_{2} (g) + Cl_{2} (g) \rightarrow 2HCl(g)

Step 2 : Find moles of H₂ gas.

The moles of H₂ can be found as

mole = \frac{grams}{MolarMass}

We have 2.0200 g of H₂ and molar mass of H₂ is 2.02 g/mol.

Let us plug in these values to find moles of H₂.

mole =\frac{2.0200g}{2.02g/mol} = 1 mol

We have 1 mol of H₂.

Step 3 : Find moles of Cl₂ using mole ratio.

The mole ratio of H₂ and Cl₂ is 1 : 1.

The moles of Cl₂ can be calculated as

1 mol H_{2} \times\frac{1 mol Cl_{2}}{1 mol H_{2}} = 1 mol Cl_{2}

Step 4 : Find grams of Cl₂.

Molar mass of Cl₂ gas is 70.096 g/mol

Mass of Cl₂ = 1 mol Cl_{2} \times\frac{70.906g}{mol} = 70.906 g

We have 70.906 grams of Cl₂

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∆G = 1.567 kJ/mole

The reaction is nonspontaneous., or will be spontaneous in the reverse direction

Explanation:

<u>Step 1:</u> The balanced equation

H2(g) + I2(g) ⇌ 2HI(g)        2.60 kJ/mol at 25°C.

<u>Step 2:</u> Data given

The initial pressures are:

pH2 = 3.10 atm

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pHI = 1.75 atm

<u>Step 3: </u>Calculate Q

Kp = (pHI)^2 / (pH2)(pI2)

Q has the same form but we substitute the non-equilibrium values given in the problem.

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<u>Step 4:</u> Calculate gibbs free energy

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= 1567.271‬ J/mole = 1.567 kJ/mole

Interpret ∆G:

∆G > 0 the reaction is nonspontaneous., or will be spontaneous in the reverse direction

∆G < 0 the reaction is spontaneous.

If ∆G  = 0 the reaction is essentially at equilibrium.

∆G = 1.567 kJ/mole

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