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3 years ago

Question 4 of 10

Physics

1 answer:

Nataly_w [17]3 years ago

3 0

Answer:

Normative

Explanation:

It is normal occurance but not unnatural

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a) CALCULATE the acceleration of a 300,000 kg jumbo jet, just before takeoff when the thrust of each of its 4 engines is 36,000

Zanzabum

Answer:

a) 0.12m/s^2

b)0.0511m/s

c)0.4258 seconds

Explanation:

$acceleration= \frac{36000}{300000}$

= 0.12m/s^2

b) 184m/h

184/3600 = 0.0511m/s

$time = \frac{0.0511}{0.12}$

Time = 0.4258 seconds

5 0

3 years ago

A.)3.33 KHz B)33.33Hz C)0.033Hz D)3.:3Hz

TEA [102]

Answer:

B 33.33Hz

Hope this helps!

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3 years ago

During a discus throw, Arthur's arm rotates 25 rad/s, and the discus is 1.5 m from the axis of rotation when he releases it. Bla

Julli [10]

Answer: Arthur

Explanation: This is a question under the concept of circular motion.

We will model the distance away from the axis of rotation as the radius of the circular motion (r).

for Arthur,

Angular speed (ω) = 25 rad/s

Radius = 1.5m

The linear (tangential) velocity is gotten as

v = ωr

v = 25 × 1.5

v = 37.5 m/s

For Blake

ω = 30 rad/s and r = 1.1m

v = ωr

v = 30 × 1.1

v = 33 m/s

Since the linear speed of Arthur's throw is faster than that of Blake's, it implies that the discus of Arthur will travel a father distance than that of Blake.

8 0

3 years ago

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A satellite is in orbit 3.117106 m from the center of Earth. The mass of Earth is 5.9821024 kg. Calculate the orbital

Dahasolnce [82]

Answer:

T = 1733.16 s = 28.88 min

Explanation:

The orbital velocity of a satellite about Earth is given as follows:

$v = \sqrt{\frac{GM}{R}}$

where,

v = orbital speed = ?

G = Gravitational Constant = 6.67 x 10⁻¹¹ Nm²/kg²

M = Mass of Earth = 5.982 x 10²⁴ kg

R = Orbit Radius = 3.117 x 10⁶ m

Therefore,

$v = \sqrt{\frac{(6.67\ x\ 10^{-11}\ Nm^{2}/kg^{2})(5.982\ x\ 10^{24}\ kg)}{(3.117\ x\ 10^{6}\ m)}}\\\\v = 11.3\ x\ 10^{3}\ m/s$

but the velocity is given as:

$v = \frac{distance}{time}$

for distance = circumference = 2πR

time = time period = T = ?

Therefore,

$11.3\ x\ 10^{3}\ m/s = \frac{2\pi(3.117\ x\ 10^{6}\ m)}{T}\\\\T = \frac{2\pi(3.117\ x\ 10^{6}\ m)}{11.3\ x\ 10^{3}\ m/s}\\\\$

T = 1733.16 s = 28.88 min

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3 years ago

A Renaissance scientist, considered possibly the greatest scientist of all time, was

a_sh-v [17]

Sir Isaac Newton lived 1643 to 1727. His main works were accomplished within the 17th century, where the Renaissance was still taking place.

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3 years ago

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