If the perimeter of the square is 4x then the domain of the function will be set of rational numbers and the domain of the function y=3x+8(3-x) is set of real numbers.
Given The perimeter of the square is f(x)=4x and the function is y=3x+8(3-x)
We will first solve the first part in which we have been given that the perimeter of the square is 4x and we have to find the domain of the function.
First option is set of rational numbers which is right for the function.
Second option is set of whole numbers which is not right as whole number involves 0 also and the side of the square is not equal to 0.
Third option is set of integers which is not right as integers involve negative number also and side of square cannot be negative.
Hence the domain is set of rational numbers.
Now we will solve the second part of the question
f(x)=3x+8(3-x)
we have not told about the range of the function so we can put any value in the function and most appropriate option will be set of real numbers as real number involve positive , negative and decimal values also.
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Answer:
5%
Step-by-step explanation:
487/9374=0.05
0.05 would translate to 5%
Hope this helps! :)
Answer:
414.72
Step-by-step explanation:
Answer:
x = 8
I dunno what the question is in the first place, but I assume you are solving for x.
Step-by-step explanation:
The two given angles are equivalent because they are parallel and they have a line that intersects.
The line creates two angles on each side of each line, which is 120 or 60 because there are 180 degs on a straight line.
The obtuse side is 120, and the -8 + 16x is also on an obtuse angle, showing that they are equal.
120 = -8 + 16x
128 = 16x
8 = x
x = 8
Answer:
The answer is 120.
Step-by-step explanation:
