Not elementary school work
We use the gas law named Charle's law for the calculation of the second temperature. The law states that,
V₁T₂ = V₂T₁
Substituting the known values,
(0.456 L)(65 + 273.15) = (3.4 L)(T₁)
T₁ = 45.33 K
Answer:
true because of the elements
Answer: ![[H^+]](https://tex.z-dn.net/?f=%5BH%5E%2B%5D)
of 0.056 M HF solution is 
Explanation:
cM 0 0
So dissociation constant will be:
Give c= 0.056 M and 
= ?
Putting in the values we get:
![[H^+]=c\times \alpha](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3Dc%5Ctimes%20%5Calpha)
![[H^+]=0.056\times 0.0016=8.96\times 10^{-5}](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D0.056%5Ctimes%200.0016%3D8.96%5Ctimes%2010%5E%7B-5%7D)
Thus of 0.056 M HF solution is
Answer:
C. Xenon
Explanation:
The question only requires you to use your visual skills to identify the unknown gas. Look at the spectra of unknown gas and xenon, are they not identical? SInce they are same, the unknown sample must be xenon.
