Answer:
Change volume / volume = .5 / 30 = .01666
coefficient of volume expansion = 3 * 24E-6 = 72E-6
Change in temp = .0167 / 24E-6 = 232 deg C
Final temp = 232 + 30 = 262 deg C
Change in volume / volume = 3 * coeff linear expansion * change in deg C
The answer is
Ekin = 1/2 * m * v^2
Ekin = 1/2 * 5,4 * 35,2^2
Ekin = 3345,41 j (joule)
Just multiply the "1.0 m/s" by ' 1 ' a few times. (Remember that a fraction with the same quantity on top and bottom is equal to ' 1 ' .)
(1.0 m/sec) · (1 km/1000 m) · (60 sec/min) · (60 min/hr) =
(1.0 · 60 · 60 / 1,000) (m · km · sec · min / sec · m · min · hr) =
(3,600 / 1,000) (km / hr) =
3.6 km/hr .
Answer:
a) 10.54 sec
b) 284.58 m
c) 29.406 m/s
d) 39.92 m/s
Explanation:
Given data:
velocity of spacecraft = 27.0 m/s
rate of free fall acceleration is 2.79 m/s^2
distance of moving aircraft from mooon surface is 155 m
a. from kinematic eqaution of motion we have
where y = 155 m
Vi = 0 as this relation is for vertical motion, so the 27.0 m/s is not included
and a = 2.79 m/s^2.
Solving for t we get
t = 10.54 sec
b.
we know that
c. from the kinematic formula
v = u + at
v = 29.4066 m/a
d.
v = 39.92 m/s