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Alina [70]
3 years ago
10

A 0.5 m3 container is filled with a fluid whose specific volume is 0.001 m3/kg. At standard gravitational acceleration, the cont

ents of this container weigh:
Physics
1 answer:
xenn [34]3 years ago
5 0

Answer: the contents of this container weighs 4905 kg.m/s²

Explanation:

Given that;

volume of a container V = 0.5 m³

we know that standard gravitational acceleration g = 9.81 m/s²

specific volume of liquid filled in the container v = 0.001 m³/kg

now we express the equation for weight of the container.

W = mg

W = (pV)g

W = Vg / ν

so we substitute

W =  (0.5 m³)(9.81 m/s ) / 0.001 m³/kg

W = 4.905 / 0.001

W = 4905 kg.m/s²

Therefore, the contents of this container weighs 4905 kg.m/s²

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Can anyone please help me on this question (DUE TOMORROW) (13 POINTS GO AWAY)
julia-pushkina [17]

4.) Quantitative: notice the root word 'quantity', which is a certain percentage of something.

a.) Quantitative, since it represents a certain percentage. The weight before the camp could also be written as an improper fraction.

b.) This is also quantitative because it can be written as a ratio(2.99:500), which can also be written as a fraction(\frac{2.99}{500} or percentage.

c.) This is qualitative. Joan has a higher percentage than Emile.

d.) Qualitative. It judges the quality of something instead of amount. To make it quantitative requires a fraction of percentage. In this case, maybe you could add how he can run y miles every x seconds.

5.)

a.)This depends on whether or not the air is moving. If the classroom's AC is on, or the window is open, then the correct unit to use is CFM (cubic feet per minute). If not, the common unit is milliliters, but must also include temperature and air pressure as well as the volume of the room.

b.)  Simply calculate the volume of the can using inches cubed, since volume is the measure of how much space an object takes up.

c.) The unit would be \frac{kg}{ft^3}. If \frac{mass}{volume} = density, then simply multiply your density by your mass.

d.) I personally would use centimeters. Inches would work too, but centimeters would be much more accurate.

e.) Use the same formula for c.), which means kilograms per cubic foot.

Hope this helped.

8 0
3 years ago
A mass is hung from a spring and set in motion so that it oscillates continually up and down. The velocity v of the weight at ti
otez555 [7]

To solve the problem it is necessary to identify the equation in the manner given above.

This equation corresponds to the displacement of a body under the principle of simple harmonic movement.

Where,

\xi = Acos(\omega t +\phi)

PART A) Our equation corresponds to

y = -5cos(4\pi t)

Therefore the value of omega is equivalent to that of

\omega = 4\pi

From the definition we know that the period as a function of angular velocity is equivalent to

T = \frac{2\pi}{\omega}

T = \frac{2\pi}{4\pi}

T = \frac{1}{2}

This same point is the equivalent of the maximum point of the speed that the body can reach, since the internal expression of the cos\thetaIs equivalent to . So the maximum speed that the body can reach is,

y = -5cos(4\pi t)

y = -5cos(4\pi (1/2))

y = -5*(-1)

y = 5

Therefore the maximum felocity will be 5ft / s

PART B) The period of graph is the time taken to reach from one maximum point to next point maximum point, then

t = \frac{T}{2} = \frac{1}{2}*\frac{1}{2}

t = \frac{1}{4}s

5 0
3 years ago
Small, icy bodies that have highly eccentric orbits and can be found in the Oort cloud or the Kuiper belt are called ____.
irina1246 [14]

Answer:

Small, icy bodies that have highly eccentric orbits and can be found in the Oort cloud or the Kuiper belt are called COMETS.

4 0
3 years ago
Inside a vacuum tube, an electron is in the presence of a uniform electric field with a magnitude of 320 N/C. (a) What is the ma
nignag [31]

(a) The magnitude of the acceleration of the electron is 5.62 x 10¹³ m/s².

(b) The speed of the electron after the given time is  4.78 x 10⁵ m/s.

<h3>Acceleration of the electron</h3>

The acceleration of the electron is calculated as follows;

F = qE

ma = qE

a = qE/m

a = (1.6 x 10⁻¹⁹ x 320)/(9.11 x 10⁻³¹)

a = 5.62 x 10¹³ m/s²

<h3>Speed of the electron</h3>

v = at

v = 5.62 x 10¹³ m/s² x  8.50 x 10⁻⁹ s

v = 4.78 x 10⁵ m/s

Learn more about speed here: brainly.com/question/4931057

#SPJ1

7 0
2 years ago
A sculpture is suspended in equilibrium by two cables, one from a wall and the other
aleksandrvk [35]

Answer:

T_1=6655.295917 \approx 6655.3N

Explanation:

From the question we are told that

Angle of cable 2 \theta=37.0\textdegree

Weight of sculpture W=5000 N

Generally the Tension from cable 2 T_2 is mathematically given by

   T_2sin37\textdegree=5000N

   T_2=5000N/sin37\textdegree

   T_2=8308.2N

Generally the Tension from Cable 1 T_1 is mathematically given by

   T_1=T_2 cos37\textdegree

   T_1=8308.2* cos 37\textdegree

   T_1=6655.295917 \approx 6655.3N

7 0
3 years ago
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