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Alina [70]
3 years ago
10

A 0.5 m3 container is filled with a fluid whose specific volume is 0.001 m3/kg. At standard gravitational acceleration, the cont

ents of this container weigh:
Physics
1 answer:
xenn [34]3 years ago
5 0

Answer: the contents of this container weighs 4905 kg.m/s²

Explanation:

Given that;

volume of a container V = 0.5 m³

we know that standard gravitational acceleration g = 9.81 m/s²

specific volume of liquid filled in the container v = 0.001 m³/kg

now we express the equation for weight of the container.

W = mg

W = (pV)g

W = Vg / ν

so we substitute

W =  (0.5 m³)(9.81 m/s ) / 0.001 m³/kg

W = 4.905 / 0.001

W = 4905 kg.m/s²

Therefore, the contents of this container weighs 4905 kg.m/s²

You might be interested in
A circular swimming pool has a diameter of 12 m. The circular side of the pool is 3 m high, and the depth of the water is 2.5 m.
Anestetic [448]

Answer:

Explanation:

Diameter of pool = 12 m

radius of pool, r = 6 m

Total height raised, h = 3 + 2.5 = 5.5 m

density of water, d = 1000 kg/m³

Mass of water, m = Volume of water x density

m = πr²h x d

m = 3.14 x 6 x 6 x 5.5 x 1000

m = 113040 kg

Work = m x g x h

W = 113040 x 9.8 x 5.5

W = 6092856 J

7 0
2 years ago
a baby carriage is sitting on the top of a hill that is 21 m high. the carriage with a baby 75kg. the carriage has what energy?
lara31 [8.8K]

Answer:

It has potential energy

PE = 15450.75 J

Explanation:

we know its potential energy because the carriage is not moving, although it can

PE = mgh

in this case, m is 75, h is 21, and g is always 9.81

plug these in: PE = (75) (21) (9.81)

your answer: PE = 15450.75 J

4 0
2 years ago
Help me please this is for physics
Yuri [45]
<h2>Hello there! :)</h2>

It's a pleasure to be helping you today with your<u> physics question!</u>

Answer:

23.1m/s

Explanation:

We want to find the initial speed of the ball.

To do this, we have to apply the formula for the time of flight of a projectile:

T=\frac{2_{v0~sin 0} }{g}

where θ = angle of flight

g = acceleration due to gravity

v0 = initial speed

Therefore, substituting the given values into the formula, we have that:

\boxed{4.2=\frac{2~x~_{v0~sin63} }{9.8}}

⇒ 2 ×_{v0} ×0.8910= 9.8 × 4.2

⇒\boxed{{v0}=\frac{9.8~times~4.2}{2~times~0.8910}}

\boxed{{v0} =23.1m/s}

That is the initial speed of the ball.

<em />

<em>I hope this helps you!</em>

<em>Good Luck with your Assignment!</em>

3 0
2 years ago
It has been suggested that a heat engine could be developed that made use of the fact that the temperature several hundred meter
lesantik [10]

Answer:

efficiency = 5.4%

Explanation:

Efficiency of heat engine is given as

\eta = \frac{W}{Q_{in}}

now we will have

W = Q_1 - Q_2

so we will have

\eta = 1 - \frac{Q_2}{Q_1}

now we know that

\frac{Q_2}{Q_1} = \frac{T_2}{T_1}

so we have

\eta = 1 - \frac{T_2}{T_1}

\eta = 1 - \frac{273+6}{273+22}

\eta = 0.054

so efficiency is 5.4%

8 0
3 years ago
An object on a spring whose constant is 30. N/m
MrRa [10]

The mass of the object is 0.0076 kg

Explanation:

The frequency of a mass-spring system (simple harmonic motion) is given by

f=\frac{1}{2\pi}\sqrt{\frac{k}{m}}

where

f is the frequency

k is the spring constant

m is the mass

For the mass-spring system in this problem, we know:

k = 30 N/m is the spring constant

f = 10 Hz is the frequency

Solving the equation for m, we find the mass:

m=\frac{k}{(2\pi f)^2}=\frac{30}{(2\pi (10))^2}=0.0076 kg

#LearnwithBrainly

3 0
2 years ago
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