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Alina [70]
3 years ago
10

A 0.5 m3 container is filled with a fluid whose specific volume is 0.001 m3/kg. At standard gravitational acceleration, the cont

ents of this container weigh:
Physics
1 answer:
xenn [34]3 years ago
5 0

Answer: the contents of this container weighs 4905 kg.m/s²

Explanation:

Given that;

volume of a container V = 0.5 m³

we know that standard gravitational acceleration g = 9.81 m/s²

specific volume of liquid filled in the container v = 0.001 m³/kg

now we express the equation for weight of the container.

W = mg

W = (pV)g

W = Vg / ν

so we substitute

W =  (0.5 m³)(9.81 m/s ) / 0.001 m³/kg

W = 4.905 / 0.001

W = 4905 kg.m/s²

Therefore, the contents of this container weighs 4905 kg.m/s²

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Answer:

The speed of the vehicle was 21 m/s

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<em>The speed of the vehicle was 21 m/s</em>

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When the mass of an object decreases, the force of gravity
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A 477 g portion of soup is heated in a microwave oven from 25°C to 90°C, using radiation with a wavelength of 1.55 × 10⁻² m. Ass
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To solve this problem we will use the heat transfer equations, to determine the amount of heat added to the body. Subsequently, through the energy ratio given by Plank, we will calculate the energy of each of the photons. The relationship between total energy and unit energy will allow us to determine the number of photons

The mass of water in the soup is 477g

The change in temperate is

\Delta T = (90+273K)-(25+273K) = 65K

Use the following equation to calculate the heat required to raise the temperature:

q = mc\Delta T

Here,

m = Mass

c = Specific Heat

q = (477)(4.184)(65)

q = 129724.92J

The wavelength of the ration used for heating is 1.55*10^{-2}m

The number of photons required is the rate between the total energy and the energy of each proton, then

\text{Number of photons} = \frac{\text{Total Energy}}{\text{Energy of one Photon}}

This energy of the photon is given by the Planck's equation which say:

E = \frac{hc}{\lambda}

Here,

h = Plank's Constant

c = Velocity of light

\lambda = Wavelength

Replacing,

E = \frac{(6.626*10^{-34})(3*10^8)}{1.55*10^{-2}}

E = 1.28*10^{-23}J

Now replacing we have,

\text{Number of photons} = \frac{82240.7}{1.28*10^{-23}}

\text{Number of photons} = 6.41*10^{27}

Therefore the number of photons required for heating is 6.41*10^{27}

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3 years ago
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