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TiliK225 [7]
3 years ago
15

Show that 1.0 m/s = 3.6 km/h . Hint: Show the explicit steps involved in converting 1.0 m/s = 3.6 km/h.

Physics
1 answer:
sergiy2304 [10]3 years ago
5 0

Just multiply the "1.0 m/s" by ' 1 ' a few times.  (Remember that a fraction with the same quantity on top and bottom is equal to ' 1 ' .)

(1.0 m/sec) · (1 km/1000 m) · (60 sec/min) · (60 min/hr) =

(1.0 · 60 · 60 / 1,000) (m · km · sec · min / sec · m · min · hr) =

(3,600 / 1,000) (km / hr) =

3.6 km/hr .

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V (Voltage)= I (Current) x R (Resistance)
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An aircraft acceleration from 100m/s to 300m/s in 100 s what is acceleration​
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(300  - 100) \div 100

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Which element does not have the same number of electrons in its outermost shell as the other elements in its group?(1 point)
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Helium (He) does not have the same number of valence electrons as other elements in its group.

The periodic table is divided into groups with the last number of the group coinciding with the number of electrons that an element in the group has in its outermost or valence shell.

Helium is in group 18 which means that it should have the same number of valence electrons as :

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4 0
3 years ago
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<h2><em>=</em><em> </em><em>179</em></h2>

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4 0
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A car travels at a steady 40.0 m/s around a horizontal curve of radius 200 m. What is the minimumcoefficient of static friction
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Answer:

c. 0.816

Explanation:

Let the mass of car be 'm' and coefficient of static friction be 'μ'.

Given:

Speed of the car (v) = 40.0 m/s

Radius of the curve (R) = 200 m

As the car is making a circular turn, the force acting on it is centripetal force which is given as:

Centripetal force is, F_c=\frac{mv^2}{R}

The frictional force is given as:

Friction = Normal force × Coefficient of static friction

f=\mu N

As there is no vertical motion, therefore, N=mg. So,

f=\mu mg

Now, the centripetal force is provided by the frictional force. Therefore,

Frictional force = Centripetal force

f=F_c\\\\\mu mg=\frac{mv^2}{R}\\\\\mu=\frac{v^2}{Rg}

Plug in the given values and solve for 'μ'. This gives,

\mu = \frac{(40\ m/s)^2}{200\ m\times 9.8\ m/s^2}\\\\\mu=\frac{1600\ m^2/s^2}{1960\ m^2/s^2}\\\\\mu=0.816

Therefore, option (c) is correct.

7 0
3 years ago
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