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3 years ago

A force of 20 N acts over an area of 2 m2. What is the pressure?

2 answers:

5 0

$\text{Given that,}\\\\\text{Force, F = 20 N.} ~ \\\\ \text{Area , A = 2 m}^2 . \\\\ \text{Pressure, P =? }\\\\P = \dfrac FA = \dfrac{20}2 = 10~~ \text{Nm}^{-2}$

Mumz [18]3 years ago

4 0

$pressure \: = \frac{force}{area } \\ \\ \\ = \frac{20N}{2m.sq} \\ \\ = 10pascal$

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2.24 m/s is the calculated velocity.

Initial velocity (u) squared plus two times the acceleration (a) times the displacement equals final velocity (v) squared (s). Final velocity (v) is equal to the square root of initial velocity (u) squared plus two times the acceleration (a) times displacement when v is the variable being solved for (s).

The cart's masses and speeds are known.

M1 = 4.00 kg, M2 = 10.0 kg, M3 = 3.00 kg, etc.

v1 = 5.00 m/s = 5.00 m/s, v2 = 3.00 m/s = 3.00 m/s, v3 = -4.00 m/s = 4.00 m/s, and m1v1+m2v2+m3v3 = (m1+m2+m3) v=d frac m 1v 1+m 2v 2+m 3v 3, where (m1+m2 + m3) is the product of (v1 v 1+m2v2+m3v3).

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the three carts' final velocities are calculated as follows: v=d frac

{4.00kg\sdot5.00m/s+10.0kg\sdot3.00m/s-3.00kg\sdot4.00m/s} 4.24m/s = 4.50kg+10.0kg+3.00kg vs. 4.50kg+10.0kg+3.00kg

5.00m/s/4.00kg/5.00m/s+10.0m/s/3.00m/s/4.00m/s =2.24m/s.

2.24 m/s is the calculated final velocity.

Learn more about velocity here-

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A force of 20 N acts over an area of 2 m2. What is the pressure? ​

A force of 20 N acts over an area of 2 m2. What is the pressure?