To solve this exercise it is necessary to take into account the concepts related to Tensile Strength and Shear Strenght.
In Materials Mechanics, generally the bodies under certain loads are subject to both Tensile and shear strenghts.
By definition we know that the tensile strength is defined as
Where,
Tensile strength
F = Tensile Force
A = Cross-sectional Area
In the other hand we have that the shear strength is defined as
where,
Shear strength
Shear Force
Parallel Area
PART A) Replacing with our values in the equation of tensile strenght, then
Resolving for F,
PART B) We need here to apply the shear strength equation, then
In such a way that the material is more resistant to tensile strength than shear force.
Increasing the mass of an object increases its momentum.
Explanation:
- Momentum of an object is measured as the quantity of motion done by the object.
- It is calculated using the formula, p = m × v where m is mass of the object and v is the velocity of the object.
- As momentum and mass vary proportionally, as seen in the formula, increasing the mass of an object will also increase its momentum.
Answer:
from the formula of work done at any angle the formula is Force *distance cosα(tita)
Answer:
a) 588.235 ohm ( all the 3 resistors are in parallel )
b) 10 A
c) Current flowing -
in 20 ohm resistor = 6.25 A
in 100 ohm resistor = 1.25 A
in 50 ohm resistor = 2.5 A
d) Voltage drop across all the resistor = 125 V
(As all the resistors are in parallel all the resistors will have the same voltage drop )
e) Power dissipated -
in 20 ohm resistor = 781.25 W
in 100 ohm resistor = 156.25 W
in 50 ohm resistor = 312.5 W
(Power = Current × Potential Difference)
