A force of 20 N acts over an area of 2 m2. What is the pressure?

2 answers:

5 0

$\text{Given that,}\\\\\text{Force, F = 20 N.} ~ \\\\ \text{Area , A = 2 m}^2 . \\\\ \text{Pressure, P =? }\\\\P = \dfrac FA = \dfrac{20}2 = 10~~ \text{Nm}^{-2}$

Mumz [18]2 years ago

4 0

$pressure \: = \frac{force}{area } \\ \\ \\ = \frac{20N}{2m.sq} \\ \\ = 10pascal$

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Answer:

I = 1.4kgm²

Explanation:

The rotational motion is caused by the frictional force, which generates a torque on the system. As there is no other force that creates a torque, this can be expressed in the equation of rotational motion below:

$\tau_f =I\alpha\\\\$

And $\tau_f=rf$ , where r is the distance from the point of application and the rotation axis, and f is the magnitude of the frictional force. This is because the frictional force is applied in the direction that causes the greatest angular acceleration (this is, 90°) and $rf\sin90\°=rf$ . Then, we have that: