I need the graph to answer your question
Answer:
6.02×10²³ particles / 1 mol
Explanation:
In this question the choices are missed.
For determine the particles of Na, in 0.25 moles we should know that the mole referrs to the Avogadro's number.
1 mol of anything contains 6.02×10²³ entities, that's why we should apply this conversion factor to find the final answer:
0.25 mol . 6.02×10²³ particles / 1 mol = 1.50×10²³ particles
In conclussion: 1.50×10²³ particles of Na are contained in 0.25 moles of Na
I believe the answer is C
Answer:
D
Explanation:
the charges need to balence out
so finding the LCM which is 12 we find we need 3x's
and 4 zs
so that makes the formula X3Z4 which is D
Answer:
Option C : Ag
Electronic configuration:
47Ag: 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d9
The d-block elements are present in the middle of periodic table between s and p-block elements. d-block elements are also called Transition elements. Their valance electrons are reside in the d orbitals. They have more electropositive character than p-block elements but less than s- block elements.
