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3 years ago

19. what is the empirical formula for C36H9?

Chemistry

2 answers:

ra1l [238]3 years ago

4 0

The empirical formula for $C_3_6 H_9$ is $C_4H$ .

Chemical formulas that give only the relative number of atoms of each type in a molecule are called empirical formulas. The subscripts in an empirical formula are always the smallest possible whole-number ratios.

Look at the ratio of these two atoms in the compound

C : H

36: 9

Divide the ratio by 9 to get simple ratio:-

C : H

36/9 : 9/9

4 : 1

For $C_3_6 H_9$ , the smallest whole number ratio is 4:1. So, the empirical formula for $C_3_6 H_9$ is $C_4H$ .

So, the empirical formula for $C_3_6 H_9$ is $C_4H$ .

To know more about:-

brainly.com/question/14044066

marusya05 [52]3 years ago

4 0

Answer:

In any empirical formula problem you must first find the mass % of the elements in the compound. ...
Then change the % to grams. ...
Next, divide all the masses by their respective molar masses. ...
Pick the smallest answer of moles and divide all figures by that.

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<u><em> calculation</em></u>

Step 1: write the balanced equation between CH3COOH + NaOH

that is CH3COOH + NaOH → CH3COONa + H2O

step 2 : find the moles of NaOH

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volume in liters = 26.90/1000=0.0269 l

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Step 3: use the mole ratio to find moles of CH3COOH

that is the mole ratio of CH3COOH: NaOH is 1:1 therefore the moles of CH3COOH is =0.0047 moles

Step 4: find the molarity of CH3COOH

molarity = moles/volume in liters

volume in liter = 5.00/1000 =0.005 l

molarity is therefore=0.0047 moles/ 0.005 l = 0.94 M

4 0

4 years ago

Please Help! Thank You

ra1l [238]

Answer:

oooooooooooooooooh i dont know this one

Explanation:

im confuzzled

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