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Kisachek [45]
3 years ago
5

Why did scientists in the 1800s decide that the list of known elements needed to be more

Chemistry
1 answer:
ankoles [38]3 years ago
8 0

Explanation:

The scientists realized that the properties of elements related to each other depending on relational properties of their atoms. They realized that atoms of different elements shared some properties depending on the number of electrons they have in their valence orbital shells and atomic mass numbers. These atomic properties determined the elements' shared properties such as texture,  reactivity, electric conductivity and etcetera. Arranging the atoms in a periodic table would therefore ideally make it easier to decipher the shared similarities and differences between atoms of different elements, such as physical and chemical properties.

Learn More:

For more on the periodic table check out these questions;

brainly.com/question/569321

brainly.com/question/1358941

#LearnWithBrainly

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What three achievements in space exploration that involved The United States
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I do not know but I think one was landing a man on the moon
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A bond between two iodine atoms would have what as the percent ionic character
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10. A "neutral atom" is one that has the same number of _______ and ______
Paladinen [302]

Answer:

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Explanation:

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8 0
3 years ago
Radioactive carbon-14 has a half life of 5730 years. Suppose a peice of wood has a decay rate of 15 disintegrations per minute.
Tom [10]

Answer:

\large \boxed{\text{2920 yr}}

Explanation:

Two important formulas in radioactive decay are

(1) \qquad t_{\frac{1}{2}} = \dfrac{\ln 2}{k}\\\\(2) \qquad \ln \left(\dfrac{N_{0}}{N}\right) = kt

1. Calculate the decay constant k

\begin{array}{rcl}t_{\frac{1}{2}} &=& \dfrac{\ln 2}{k}\\\\\text{1530 yr} &= &\dfrac{\ln 2}{k}\\\\k & = & \dfrac{\ln 2}{\text{1530 yr}}\\\\& = & 4.530 \times 10^{-4} \text{ yr}^{-1}\\\end{array}

2. Calculate the time

\begin{array}{rcl}\ln \left(\dfrac{N_{0}}{N}\right) &= &kt \\\\\ln \left(\dfrac{15}{4}\right) &= &4.530 \times 10^{-4} \text{ yr}^{-1}\times t \\\\\ln 3.75 &= &4.530 \times 10^{-4} \text{ yr}^{-1}\times t \\t &= &\dfrac{\ln 3.75}{4.530 \times 10^{-4} \text{ yr}^{-1}}\\\\& = & \textbf{2920 yr}\\\end{array}\\\text{It would take $\large \boxed{\textbf{2920 yr}}$ for the rate to decrease to 4 dis/min.}

5 0
4 years ago
How do you answer this chem equation: <br><br> 836.8J=14.5g*Cm*64
Alja [10]
Is that a thing? Maybe you've said it wrong. Otherwise, I don't think you don't learn this in middle school.

8 0
4 years ago
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