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3 years ago

What is the affect of neutrons on atoms

Chemistry

1 answer:

Evgen [1.6K]3 years ago

7 0

Answer:

It's better to explain it.

Explanation:

Neutrons do not affect the electron configuration, but the sum of atomic number and the number of neutrons, or neutron number, is the mass of the nucleus. You know that neutrons are found in the nucleus of an atom. Under normal conditions, protons and neutrons stick together in the nucleus. During radioactive decay, they may be knocked out of there. Neutron numbers are able to change the mass of atoms, because they weigh about as much as a proton and electron together. if your asking What is the role of a neutron in an atom? then, Neutrons are very important in providing stability for an atom. Some atoms don't "need" neutrons - The hydrogen atom does not have any neutrons. However, as the atomic number ( # of protons ) increases, the number of neutrons increases as well.

Protons don't like each other. Naturally, 'positive charges repel', so it wouldn't be possible to have more than one proton in the nucleus. Here's where the neutron comes in.

Hope this helps. :)

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A student weighs a sample of sugar and records the measurement. He then writes down his observations on

Firdavs [7]

Answer:

Because the student made use of scientific instruments in one case and his senses in the other.

Explanation:

Scientific experiments involve making observations, which is key to the outcome of any experiment. According to the scientific method, collecting of data is one of the steps in fulfilling the scientific procedure. One way to collect data is by using scientific instruments to measure, which is then recorded. This is the case for the WEIGHT of the sugar the student recorded.

Another way to collect data is by making use of the senses e.g eyes, nose, skin etc. to observe and record the perceived information. Therefore, the pieces of information collected by the student represent DATA because he made use of his senses and scientific instruments.

6 0

3 years ago

How many nonmetal elements are on the periodic table of elements

vladimir1956 [14]

There are 17 nonmetals on the periodic table of elements.

3 0

2 years ago

Read 2 more answers

A compression, at a constant pressure of 140 kPa, is performed on 4.0 moles of an ideal monatomic gas (Cv = 3/2 R). The compress

kobusy [5.1K]

<u>Answer:</u> The change in internal energy of the gas is 29.414 kJ.

<u>Explanation:</u>

To calculate the temperature of the gas at different volumes, we use ideal gas equation:

$PV=nRT$

When volume = $0.26m^3$

We are given:

Conversion used: $1m^3=1000L$

$P=140kPa\\V=0.23m^3=260L\\n=4.0mol\\R=8.31\text{L kPa }mol^{-1}K^{-1}$

Putting values in above equation:

$140kPa\times 260L=4mol\times 8.31\text{L kPa }mol^{-1}K^{-1}\times T_i\\\\T_i=1095.06K$

When volume = $0.12m^3$

We are given:

$P=140kPa\\V=0.12m^3=120L\\n=4.0mol\\R=8.31\text{L kPa }mol^{-1}K^{-1}$

Putting values in above equation:

$140kPa\times 120L=4mol\times 8.31\text{L kPa }mol^{-1}K^{-1}\times T_f\\\\T_f=505.41K$

To calculate the change in internal energy, we use the equation:

$\Delta U=nC_v\Delta T=nC_v(T_f-T_i)$

where,

$\Delta U$ = change in internal energy = ?

n = number of moles = 4.0 mol

$C_v$ = heat capacity at constant volume = $\frac{3}{2}R$

$T_f$ = final temperature = 1095.06 K

$T_i$ = initial temperature = 505.41 K

Putting values in above equation, we get:

$\Delta U=4\times \frac{3}{2}\times 8.314J/K.mol\times (505.41-1095.06)\\\\\Delta U=29414.1J$

Converting this value in kilojoules, we use the conversion factor:

1 kJ = 1000 J

So, $29414.1J=\frac{1kJ}{1000J}\times 29414.1J=29.414kJ$

Hence, the change in internal energy of the gas is 29.414 kJ.

6 0

3 years ago

a 4 kilogram cat is resting on top of a bookshelf that is 3 meters high what is the cats gravitational potential energy relative

Citrus2011 [14]

GPE = mgh

Where GPE is gravitational potential energy (J), m is the mass ob the object (kg), g is acceleration due to gravity (m/s²) and h is the height (m)

m = 4 kg
g = 9.8 m/s²
h = 3 m

By substitution,
GPE = 4 kg x 9.8 m/s² x 3 m
= 117.6 J
≈ 118 J

Hence, the answer is D

4 0

2 years ago

Calculate the amount in moles and grams of KMnO4 present in 3dm^3 of 0.25M

Stels [109]

Answer:

Number of moles = 0.75 mol

Mass = 118.5 g

Explanation:

Given data:

Number of moles of KMnO₄ = ?

Mass in gram = ?

Molarity of KMnO₄ = 0.25 M

Volume of KMnO₄ solution = 3 dm³ (3 L)

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles / L of solution

0.25 M = number of moles / 3 L

Number of moles = 0.25 M× 3 L

M = mol/L

Number of moles = 0.75 mol

Mass in gram:

Mass = number of moles × molar mass

Mass = 0.75 mol × 158 g/mol

Mass = 118.5 g

5 0

2 years ago