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mojhsa [17]
3 years ago
6

What is the best example

Physics
1 answer:
irinina [24]3 years ago
8 0

B. heat is correct answer

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After hitting the spring, the block is bounced back up the ramp. The maximum compression of the spring is Δx=0.03m, and the spri
Lyrx [107]

Answer:

v = 1.28 m/s

Explanation:

Given that,

Maximum compression of the spring, \Delta x=0.03\ m

Spring constant, k = 800 N/m

Mass of the block, m = 0.2 kg

To find,

The velocity of the block when it first reaches a height of 0.1 m above the ground on the ramp.

Solution,

When the block is bounced back up the ramp, the total energy of the system remains conserved. Let v is the velocity of the block such that,

Initial energy = Final energy

\dfrac{1}{2}kx^2=mgh+\dfrac{1}{2}mv^2

Substituting all the values in above equation,

\dfrac{1}{2}\times 800\times 0.03^2=0.2\times 9.8\times 0.1+\dfrac{1}{2}\times 0.2\times v^2

v = 1.28 m/s

Therefore the velocity of block when it first reaches a height of 0.1 m above the ground on the ramp is 1.28 m/s.

5 0
3 years ago
Different ____ of light through two separate mediums causes the bending of waves fronts associated with light rays.
Fittoniya [83]

Different speeds of light through two separate media ... and the difference in wavelength caused by the difference ... causes the bending of waves fronts associated with light rays.

AFTER the bend, since the light rays then travel in a different direction, we may also say that the 'velocity' has changed.

8 0
3 years ago
The intensity I of light varies inversely as the square of the distance D from the source. If the intensity of illumination on a
emmasim [6.3K]

The intensity on a screen 20 ft from the light will be 0.125-foot candles.

<h3>What is the distance?</h3>

Distance is a numerical representation of the length between two objects or locations.

The intensity I of light varies inversely as the square of the distance D from the source;

I∝(1/D²)

The ratio of the intensity of the two cases;

\rm \frac{I_1}{I_2} =(\frac{D_2}{D_1} )^2\\\\ \rm \frac{2}{I_2} =(\frac{20}{5} )^2\\\\ \frac{2}{I_2} =4^2 \\\\ I_2= \frac{2}{16} \\\\  I_2= 0.125 \ foot-candles

Hence, the intensity on a screen 20 ft from the light will be 0.125 foot-candles

To learn more about the distance refer to the link;

brainly.com/question/26711747

#SPJ1

6 0
2 years ago
A car of mass 998 kilograms moving in the positive y–axis at a speed of
aksik [14]
The total momentum should come out to be  <span>2.0 x 10^4 kilogram meters/second </span>
8 0
3 years ago
Read 2 more answers
Which part of the electromagnetic spectrum has a lower frequency than visible light?
Mademuasel [1]

The Correct Answer is <u>D.Infrared/</u> <em>INFARED has a lower frequency than visible light/</em>

6 0
3 years ago
Read 2 more answers
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