Answer:
39267.96 Hz
Explanation:
Given:
Frequency emitted = 16246 Hz
Speed of source = 141 m/s
Speed of observer = 141 m/s
Let the velocity of sound is v = 340 m/s
Doppler effect is nothing but the change in the wavelength or frequency of a wave relative to the observer, who is also moving relative to the origin of the wave source.
Therefore, Doppler effect when the source and the observer moves towards each other,
Frequency heard = ( frequency emitted ) ( Velocity of sound + Speed of the observer ) / ( velocity of sound - speed of source )
16246 x ( 340 + 141 ) / ( 340 - 141 )
= 39267.96 Hz
Answer:
I think you just have to input the horizontal velocity component.
Explanation:
Assuming no air resistance
The horizontal velocity is constant at
vx = 17.5cos71 = 5.6974... = 5.70 i m/s
The vertical velocity varies with gravity
vy = 17.5sin71 + -9.81(22) = -199.273... = -199 j m/s
v = 5.70i - 199j m/s
arguably one should round to only two significant digits
Answer:
The acceleration of the cart is 1.0 m\s^2 in the negative direction.
Explanation:
Using the equation of motion:
Vf^2 = Vi^2 + 2*a*x
2*a*x = Vf^2 - Vi^2
a = (Vf^2 - Vi^2)/ 2*x
Where Vf is the final velocity of the cart, Vi is the initial velocity of the cart, a the acceleration of the cart and x the displacement of the cart.
Let x = Xf -Xi
Where Xf is the final position of the cart and Xi the initial position of the cart.
x = 12.5 - 0
x = 12.5
The cart comes to a stop before changing direction
Vf = 0 m/s
a = (0^2 - 5^2)/ 2*12.5
a = - 1 m/s^2
The cart is decelerating
Therefore the acceleration of the cart is 1.0 m\s^2 in the negative direction.
