The equatorial radius of the earth is
r = 6378 km = 6378 x 10³ m
The earth makes 1 revolution in 24 hours.
The angular velocity is
ω = (2π rad)/(24*3600 s) = 7.2722 x 10⁻⁵ rad/s
The tangential velocity (linear velocity) at a point on the equator is
v = rω
= (6378 x 10³ m)*(7.2722 x 10⁻⁵ rad/s)
= 463.8 m/s
Answer: 463.8 m/s
Answer:
Explanation:
The Hi line of the Balmer series is emitted in the transition from n = 3 to n = 2 i.e. 
and 
The wavelength of Hi line of the Balmer series is given by :
So, the wavelength for this line is 550 nm. Hence, this is the required solution.
The phase is called 3rd quarter.
Hope this helps:)
distance(d) = speed(s) × time (t)
= 22.3 × 8.5
= 189.55m
-- Charges with the same sign repel each other.
-- Charges with different signs attract each other.
-- This is called the "electrostatic force".
-- There's another set of forces called "magnetic forces", but
-- there's no such thing as "electromagnetic force".
