Bella’s average velocity is about 0.693 meters per second.
To find the average velocity, you must divide the distance by the change in time, which should look like v=d/t
Here is how you set up the equation-
v=6.1/8.8
Once you divide 6.1 meters by 8.8 seconds, you should get a number that looks like 0.69318182.... however, I just rounded it to 0.693 meters per second. You can round it to whatever you like.
Hope this helped! If you have any questions about what I mentioned in my answer or explanation, feel free to comment on my answer and I’ll try to get back to you!
Answer:
The voltage drop across the bulb is 115 V
Explanation:
The voltage drop equation is given by:

Where:
ΔW is the total work done (4.6kJ)
Δq is the total charge
We need to use the definition of electric current to find Δq

Where:
I is the current (2 A)
Δt is the time (20 s)


Then, we can put this value of charge in the voltage equation.

Therefore, the voltage drop across the bulb is 115 V.
I hope it helps you!
Weight = (mass) x (gravity)
On Earth ...
Weight = (1 kg) x (9.8 m/s^2)
Weight = 9.8 Newtons
I think the correct answer from the choices would be that metals donate electrons to nonmetals. Ionic bonding involves transfer of valence electrons. The metal looses its valence electrons which makes it a cation while the nonmetal accepts these electrons.
The magnitude of gravity is expressed in terms of its acceleration. So the magnitude of ' g ' at that altitude is exactly 6.5 m/s^2.