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jekas [21]
2 years ago
12

Use the ________ tag to configure a generic area on a web page that is embedded within a paragraph or other block display elemen

t.
Computers and Technology
1 answer:
Dvinal [7]2 years ago
4 0

Answer:

Use the HTML <p> tag to configure a generic area on a web page that is embedded within a paragraph or other block display element.

Explanation:

Example:

<p> This is some text in a paragraph. </p>

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Suppose we wanted to make change for purchases and wanted to use the least number of coins possible. Here is a greedy algorithm:
love history [14]

Answer:

Explanation:

The following code is a Python function that takes in the amount of change. Then it uses division and the modulo operator to calculate the number of coins that make up the changes, using the greatest coin values first.

import math

def amountOfCoins(change):

   print("Change: " + str(change))

   quarters = math.floor(change / 0.25)

   change = change % 0.25

   dimes = math.floor(change / 0.20)

   change = change % 0.20

   pennies = math.floor(change / 0.01)

   print("Quarters: " + str(quarters) + "\nDimes: " + str(dimes) + "\nPennies: " + str(pennies))

5 0
3 years ago
5.
larisa86 [58]

Answer:

Explanation:

5 is correct answer

3 0
2 years ago
⦁ Consider transferring an enormous file of L bytes from Host A to Host B. Assume an MSS of 536 bytes. ⦁ What is the maximum val
timurjin [86]

Answer:

a)  There are approximately  2^32 = 4,294,967,296 possible number of the sequence. This number of the sequence does not increase by one with every number of sequences but by byte number of data transferred. Therefore, the MSS size is insignificant. Thus, it can be inferred that the maximum L value is representable by 2^32 ≈ 4.19 Gbytes.

b)  ceil(2^32 / 536) = 8,012,999

The segment number is 66 bytes of header joined to every segment to get a cumulative sum of 528,857,934 bytes of header. Therefore, overall number of bytes sent will be 2^32 + 528,857,934 =  4.824 × 10^9 bytes.  Thus, we can conclude that the total time taken to send the file will be 249 seconds over a 155~Mbps link.

Explanation:

a)  There are approximately  2^32 = 4,294,967,296 possible number of the sequence. This number of the sequence does not increase by one with every number of sequences but by byte number of data transferred. Therefore, the MSS size is insignificant. Thus, it can be inferred that the maximum L value is representable by 2^32 ≈ 4.19 Gbytes.

b)  ceil(2^32 / 536) = 8,012,999

The segment number is 66 bytes of header joined to every segment to get a cumulative sum of 528,857,934 bytes of header. Therefore, overall number of bytes sent will be 2^32 + 528,857,934 =  4.824 × 10^9 bytes.  Thus, we can conclude that the total time taken to send the file will be 249 seconds over a 155~Mbps link.

8 0
2 years ago
The________ format is usually used to store data
Nikitich [7]
The answer is BCD; The BCD format is usually used to store data
5 0
3 years ago
For this exercise, you are going to complete the printScope() method in the Scope class. Then you will create a Scope object in
iragen [17]

Answer:

Explanation:

The following is the entire running Java code for the requested program with the requested changes. This code runs perfectly without errors and outputs the exact Sample Output that is in the question...

public class ScopeTester

{

public static void main(String[] args)

{

       Scope scope = new Scope();

       scope.printScope();

}

}

public class Scope

{

private int a;

private int b;

private int c;

public Scope(){

a = 5;

b = 10;

c = 15;

}

public void printScope(){

       System.out.println("a = " + a);

       System.out.println("b = " + b);

       System.out.println("c = " + c);

       System.out.println("d = " + getD());

       System.out.println("e = " + getE());

}

public int getA() {

return a;

}

public int getB() {

return b;

}

public int getC() {

return c;

}

public int getD(){

int d = a + c;

return d;

}

public int getE() {

int e = b + c;

return e;

}

}

4 0
2 years ago
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