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2 years ago

9

The sugars produced by photosynthesis are stored and later may be consumed by an organism such as a deer, mouse, or human. The c

hemical energy in the stored sugars is an example of kinetic energy or potential energy

1 answer:

Andre45 [30]2 years ago

3 0

Answer: This isn't a question but the statement is quite accurate to a well thought out science lesson.

You might be interested in

What is meant by the term resistance?

kondor19780726 [428]

Answer:

Definiton 1.the refusal to accept or comply with something; the attempt to prevent something by action or argument

Definition 2. the ability not to be affected by something, especially adversely

Definition 3. the impeding, slowing, or stopping effect exerted by one material thing on another

Definiton 4: the degree to which a substance or device opposes the passage of an electric current, causing energy dissipation. Ohm's law resistance (measured in ohms) is equal to the voltage divided by the current.

Explanation:

<em>Hope this Helps! If not Correct me!</em>

5 0

3 years ago

Human activities can have an impact on Earth's systems. Which Earth system is most affected when factories burn harmful chemical

IgorC [24]

Answer:

Hey

Your answer would be Earth's atmospheric system

Over time of cousre it will effect Earth's intire surface.

DON'T DRIVE MORE THAT YOU HAVE TO, SAVE THE EARTH!

7 0

3 years ago

A solid conducting sphere with radius RR that carries positive charge QQ is concentric with a very thin insulating shell of radi

svetlana [45]

Answer:

$E=0$ at r < R;

$E=\frac{1}{4\pi\epsilon}\frac{Q}{r^{2}}$ at 2R > r > R;

$E=\frac{1}{4\pi\epsilon} \frac{2Q}{r^{2}}$ at r >= 2R

Explanation:

Since we have a spherically symmetric system of charged bodies, the best approach is to use Guass' Theorem which is given by,

$\int {E} \, dA=\frac{Q_{enclosed}}{\epsilon}$ (integral over a closed surface)

where,

$E$ = Electric field

$Q_{enclosed}$ = charged enclosed within the closed surface

$\epsilon$ = permittivity of free space

Now, looking at the system we can say that a sphere(concentric with the conducting and non-conducting spheres) would be the best choice of a Gaussian surface. Let the radius of the sphere be r .

at r < R,

$Q_{enclosed}$ = 0 and hence $E$ = 0 (since the sphere is conducting, all the charges get repelled towards the surface)

at 2R > r > R,

$Q_{enclosed}$ = Q,

therefore,

$E\times4\pi r^{2}=\frac{Q_{enclosed}}{\epsilon}$

(Since the system is spherically symmetric, E is constant at any given r and so we have taken it out of the integral. Also, the surface integral of a sphere gives us the area of a sphere which is equal to $4\pi r^{2}$ )

or, $E=\frac{1}{4\pi\epsilon}\frac{Q}{r^{2}}$

at r >= 2R

$Q_{enclosed}$ = 2Q

Hence, by similar calculations, we get,

$E=\frac{1}{4\pi\epsilon} \frac{2Q}{r^{2}}$

4 0

4 years ago

A car travels along a straight road, heading east for 1 h, then traveling for 30 min on another road that leads northeast. If th

Bogdan [553]

Answer:

The car is 72.75 miles away from its starting position.

Explanation:

First, remember the relation:

distance = time*speed.

Also, the distance between two points (a, b) and (c, d) is:

D = √( (a - c)^2 + (b - d)^2)

For this problem, we can assume:

The North is equivalent to the y-axis, and the East is equivalent to the x-axis.

We also assume that the initial position of the car is (0mi, 0mi)

Now the car moves to the East at a speed of 52mi/h for one hour, then the new position of the car is:

(0mi, 0mi) + (52mi/h*1h, 0mi) = (52mi, 0mi)

Now the car travels 30 mins (or 0.5 hours) to the northeast at a speed of 52mi/h.

We can assume that it moves at an exact angle of 45° from East to North, then the components of the speed can be written as:

Sx = speed in the x-axis = 52mi/h*cos(45°) = 36.77 mi/h

Sy = speed in the y-axis = 52mi/h*sin(45°) = 36.77 mi/h

Then the new position of the car is:

(52mi, 0mi) + (36.77 mi/h*0.5h, 36.77 mi/h*0.5h) = (70.385 mi, 18.385 mi)

Now we know the final position of the car.

The distance between the final position (70.385 mi, 18.385 mi) and the initial position (0mi, 0mi) is:

D = √( (70.385 mi - 0mi)^2 + (18.385 mi - 0mi)^2) = 72.75 mi

The car is 72.75 miles away from its starting position.

7 0

3 years ago

What is calcium use bullets please

madam [21]

The chemical element of atomic number 20. A soft grey metal. hope this helps.

7 0

4 years ago