Answer:
a = -0.59 m/s^2
v = 0.22 m/s
Explanation:
The equation of motion in simple harmonic motion is defined as
where A is the amplitude, ω is the angular frequency, and Ф is the phase angle which has to be determined by initial conditions.
The period of the motion is given, so the angular frequency could be calculated.
The initial conditions are not given in the question, so I will assume that at t = 0, the block is at the origin (x = 0). (This assumption will not affect our final result, we can as well choose another initial point.)
Let’s find the time when x = 0.160 m.
The velocity function is the derivative of the position function with respect to time.
Similarly, the acceleration function is the derivative of velocity function with respect to time.
A) 
B) 
Answer:
<h2>9.375Nm</h2>
Explanation:
The formula for calculating torque τ = Frsin∅ where;
F = applied force (in newton)
r = radius (in metres)
∅ = angle that the force made with the bar.
Given F= 25N, r = 0.75m and ∅ = 30°
torque on the bar τ = 25*0.75*sin30°
τ = 25*0.75*0.5
τ = 9.375Nm
The torque on the bar is 9.375Nm
Answer:
The equation of displacement is 
.
Explanation:
Given that,
Distance = 2.50 m
We need to calculate the equation of wave
Using general equation of wave
....(I)
Where, A = amplitude
t = time
x = displacement
= phase difference
Put the value in the equation
At t = 0, x = 0, y =A
From equation (I)
Hence, The equation of displacement is .
Explanation:
The given data is as follows.
F = 
q = 
v = 385 m/s
= 0.876
Now, we will calculate the magnitude of magnetic field as follows.
B = 
= 
= 
T
= 10.65 T
Thus, we can conclude that magnitude of the magnetic field is 10.65 T.
